4s+7a=861
s+a=168
This can be solved using either elimination or substitution. I am going to use substitution.
Solve s+a=168 for s
s=168-a
Replace 168-a for s in 4s+7a=861
4(168-a)+7a=861
672-4a+7a=861
Solve for a
672+3a=861
3a=189
a=63
Substitute 63 for a in s=168-a
s=168-63=105
So, s=105 student tickets and a=63 adult tickets
Answer:
A.
Step-by-step explanation:
From the given information:
If A = m × n matrix
where;
b is a vector in 
Then; the statement that doesn't fit and is not related to the other three from the given options is Option A.
This is because the statement in Option A appears to be inconsistent. For the model Ax=b to have a solution, A must be non-singular and b must be in A's column space.
Option c and d are equivalent, also option b and c are equivalent.
: 88, 87, 89 90, 87, 85, 88, 91, 86, 86, 88, 89<br>what's is the inerquartile range
andreyandreev [35.5K]
I think 88 i don’t really know
I believe its... 21 × 10 = 210