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What is 3a+2c=26 solve for a and c

blondinia [14]

Simplifying

3a + 2b + c = 26

Solving

3a + 2b + c = 26

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-2b' to each side of the equation.

3a + 2b + -2b + c = 26 + -2b

Combine like terms: 2b + -2b = 0

3a + 0 + c = 26 + -2b

3a + c = 26 + -2b

Add '-1c' to each side of the equation.

3a + c + -1c = 26 + -2b + -1c

Combine like terms: c + -1c = 0

3a + 0 = 26 + -2b + -1c

3a = 26 + -2b + -1c

Divide each side by '3'.

a = 8.666666667 + -0.6666666667b + -0.3333333333c

Simplifying

a = 8.666666667 + -0.6666666667b + -0.3333333333c

3 0

2 years ago

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In 5 OR MORE SENTENCES, write a short story explaining the graph OR write about the key features of the graph.

rewona [7]

The graph illustrated is divided into three seperate sections namely A, B and C, the short story culled from the graph is described thus:

Rate of change or slope = (Rise/ Run)

Rise = y2 - y1
Run = x2 - x1

SECTION A:

Slope = (40 - 0) ÷ (20 - 0) = 40/20 = 2

Distance traveled = 50 meters

SECTION B :

This section gives an horizontal line, hence, the slope is 0.

Distance covered = 0 ; as there was no change in the distance over the period of time.

SECTION C:

Slope = (80 - 50) ÷ (70 - 60) = 30/10 = 3

The total distance traveled = 80 - 50 = 30 meters

The total distance and time spent traveling :

Total distance traveled = (50 + 30) = 80 meters

Total time spent = 70 seconds (time at the 80 meter mark)

Hence, the story.

Learn more : brainly.com/question/25309609

6 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

astra-53 [7]

Answer:

$3\pi \rightarrow y=2\cos \dfrac{2x}{3}\\ \\\dfrac{2\pi }{3}\rightarrow y=6\sin 3x\\ \\\dfrac{\pi }{3}\rightarrow y=-3\tan 3x\\ \\10\pi \rightarrow y=-\dfrac{2}{3}\sec \dfrac{x}{5}$

Step-by-step explanation:

The period of the functions $y=a\cos(bx+c)$ , $y=a\sin(bx+c)$ , $y=a\sec (bx+c)$ or $y=a\csc(bx+c)$ can be calculated as

$T=\dfrac{2\pi}{b}$

The period of the functions $y=a\tan(bx+c)$ or $y=a\cot(bx+c)$ can be calculated as

$T=\dfrac{\pi}{b}$

A. The period of the function $y=-3\tan 3x$ is

$T=\dfrac{\pi}{3}$

B. The period of the function $y=6\sin 3x$ is

$T=\dfrac{2\pi}{3}$

C. The period of the function $y=-4\cot \dfrac{x}{4}$ is

$T=\dfrac{\pi}{\frac{1}{4}}=4\pi$

D. The period of the function $y=2\cos \dfrac{2x}{3}$ is

$T=\dfrac{2\pi}{\frac{2}{3}}=3\pi$

E. The period of the function $y=-\dfrac{2}{3}\sec \dfrac{x}{5}$ is

$T=\dfrac{2\pi}{\frac{1}{5}}=10\pi$

5 0

3 years ago

Show steps for x+7=19

marishachu [46]

Answer:

x=12

Step-by-step explanation:

x+7=19

-7 -7

x=12

7 0

2 years ago

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Please help me and the answer is not the first one

Anna11 [10]

I think it’s the second one!!!

5 0

3 years ago

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