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3 years ago

Please help with geomtry

Mathematics

1 answer:

crimeas [40]3 years ago

5 0

Here are the answers you were looking for:

A) Yes

B) No

C) No

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3x + 8y = 12 2x + 2y = 3 Part A: Create an equivalent system of equations by replacing one equation with the sum of that equatio

love history [14]

Ok here is what I think.
Let us first number these statements, as #1, and #2.
First statement: 3x + 8y = 12 (1)
Second Statement: 2x + 2y = 3 (2)
Now, we can work from this.
We want to make one of the equations be equal to 0 so that at the end when we check they can be equal to each other.
Let us use 4.
3x+8y=12 1-8x-8y=-12 2
This gives us:-5x = 0
Now we should try and isolate x so we can substitute it into one of the equations.
We have -5x=0
and x=0
3(0)+8y=12
8y=12
y=12/8
y=3/2
Plug in these new equations
y=3/2 and y=0 into any of the first equations
3x+8y=12 3(0)+8(3/2)= 12 8(3/2)=12 4(3)=12 12=12
Now we know it works, thats our check^^

7 0

3 years ago

Find an equation of the line perpendicular to the graph of 14x-7=1 that passes through the point at (-2,4)

wolverine [178]

we know that

If two lines are perpendicular, then the product o their slopes is equal to minus one

$m1*m2=-1$

Step 1

<u>Find the slope of the given line</u>

we have

$14x-7=1\\14x=1+7$

$x=8/14$ -------> $x=4/7$

This line is parallel to the y-axis

the perpendicular will be parallel to the x-axis

Step 2

The equation of the line perpendicular to the given line is the y-coordinate of the given point

Point $(-2,4)$

the equation is

$y=4$

therefore

<u>the answer is</u>

$y=4$

see the attached figure to better understand the problem

5 0

3 years ago

What decimal is 0.99 less than 5

gladu [14]

In order to solve the problem what you must do is 5- .99 to get 5.01

3 0

3 years ago

Factor 20r+60t to identify the equivalent expression

Nadusha1986 [10]

Answer:

$\boxed{20(r + 3t)}$

Step-by-step explanation:

$20r + 60t$

Factor out 20 from the expression.

$20(r) + 20(3t)$

Take 20 as common.

$20(r + 3t)$

7 0

3 years ago

Can I get some help on this I have so many assignments to do and I just want to go to sleep

AfilCa [17]

Hi! It’s me from your other post! Here’s my work for you! It’s been awhile since I’ve done this stuff so I’m really sorry if I get you a bad grade! I just wanted to help out:))

7 0

2 years ago