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3 years ago

Simplify. a - {4 b - [ a - (5 b - c ) + 3 c - ( a - b - 9 c )]}

1 answer:

7 0

The answer to this should be a-8b+13c

a - {4b - [a - (5b - c) + 3c - (a - b - 9c)]}
=a - {4b - [a - 5b + c + 3c - a + b + 9c]}
=a - {4b - [- 4b+ 13c]}
=a - {4b + 4b -13c}
=a - 8b + 13c

Hope this helped :)
Have a great day

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Answer:

y≥6−x

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2 popcorn 5 pretzel

Step-by-step explanation:

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3 years ago

Help!! 50 points and brainliest!

Viktor [21]

Answer:

Second choice:

$x=2t$

$y=4t^2+4t-3$

Fifth choice:

$x=t+1$

$y=t^2+4t$

Step-by-step explanation:

Let's look at choice 1.

$x=t+1$

$y=t^2+2t$

I'm going to subtract 1 on both sides for the first equation giving me $x-1=t$ . I will replace the $t$ in the second equation with this substitution from equation 1.

$y=(x-1)^2+2(x-1)$

Expand using the distributive property and the identity $(u+v)^2=u^2+2uv+v^2$ :

$y=(x^2-2x+1)+(2x-2)$

$y=x^2+(-2x+2x)+(1-2)$

$y=x^2+0+-1$

$y=x^2$

So this not the desired result.

Let's look at choice 2.

$x=2t$

$y=4t^2+4t-3$

Solve the first equation for $t$ by dividing both sides by 2:

$t=\frac{x}{2}$ .

Let's plug this into equation 2:

$y=4(\frac{x}{2})^2+4(\frac{x}{2})-3$

$y=4(\frac{x^2}{4})+2x-3$

$y=x^2+2x-3$

This is the desired result.

Choice 3:

$x=t-3$

$y=t^2+2t$

Solve the first equation for $t$ by adding 3 on both sides:

$x+3=t$ .

Plug into second equation:

$y=(x+3)^2+2(x+3)$

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

$y=(x^2+6x+9)+(2x+6)$

$y=(x^2)+(6x+2x)+(9+6)$

$y=x^2+8x+15$

Not the desired result.

Choice 4:

$x=t^2$

$y=2t-3$

I'm going to solve the bottom equation for $t$ since I don't want to deal with square roots.

Add 3 on both sides:

$y+3=2t$

Divide both sides by 2:

$\frac{y+3}{2}=t$

Plug into equation 1:

$x=(\frac{y+3}{2})^2$

This is not the desired result because the $y$ variable will be squared now instead of the $x$ variable.

Choice 5:

$x=t+1$

$y=t^2+4t$

Solve the first equation for $t$ by subtracting 1 on both sides:

$x-1=t$ .

Plug into equation 2:

$y=(x-1)^2+4(x-1)$

Distribute and use the binomial square identity used earlier:

$y=(x^2-2x+1)+(4x-4)$

$y=(x^2)+(-2x+4x)+(1-4)$

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$y=x^2+2x-3$ .

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3 years ago

Read 2 more answers

A test of abstract reasoning is given to a random sample of students before and after they completed a formal logic course. The

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Answer:

The right answer is " $0.2$ ".

Step-by-step explanation:

The given values are:

$\bar{x_0} = 3.7$

$s_o=4.95$

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As we know,

95% confidence for $\mu_0$ will be:

= $\bar{x_0} \pm t_{\frac{0.05}{2} },n-1\times \frac{s_o}{\sqrt{n} }$

The lower bound will be:

= $3.7-2.2621\times \frac{4.95}{\sqrt{10} }$

= $0.16\simeq 0.2$

The upper bound will be:

= $3.7+2.2621\times \frac{4.95}{\sqrt{10} }$

= $7.23\simeq7.2$

Thus the right answer is " $0.2$ "

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Answer:

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Step-by-step explanation:

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o-na [289]

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Mean weight of the 20 backpacks = 220 ÷ 20 = 11 pounds

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Answer: The mean weight of the 20 backpacks is 11 pounds
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3 years ago