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earnstyle [38]
2 years ago
9

Leslie is ordering matching shirts for the debate team. They can get sweaters, sweatshirts, T-shirts, polo shirts, or turtleneck

s. Each type of shirt comes in yellow, red, orange, green, or blue. Their logo can be shaped like a diamond, a rectangle, a star, a bird, or a pencil. Given these choices, how many different combinations does Leslie have to choose from?
Mathematics
2 answers:
goldenfox [79]2 years ago
5 0
Sweater, sweatshirt, t-shirt, polo, turtle
5 shirt choices

colors, there are 5 of those

5 designs

if we asssuume that each one has to have a color and a design, then
the answer is 5*5*5 or 125 combinations
alexgriva [62]2 years ago
4 0
THE ANSWER is 25 different  combinations
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The equations of three lines are given below.
Yuliya22 [10]

Step-by-step explanation:

line 1 and 2 : parallel

as line 2 is actually

6x + 2y = 8

2y = -6x + 8

y = -3x + 4

so, they have the same slope (factor of x).

line 1 and 3 : neither

the slopes -3 and 3 are not parallel not perpendicular (90°).

line 2 and 3 : neither

as line 2 is parallel to line 1, it has the same relationship to line 3 as line 1.

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Ms. Wood spills a milkshake on a rectangular piece of paper as shown below. Which of the following best approximates the area of
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b.300cm

Step-by-step explanation:

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3 years ago
Space Shuttle has three computers. Computer A is a primary computer and Computer B and Computer C are auxiliary computers. There
sweet-ann [11.9K]

Answer:

Required probability equals 0.18%

Step-by-step explanation:

The probability that the primary and one auxiliary computer fails equals

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2)Probability that A and C fails

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3 years ago
In the triangle pictured, let A, B, C be the angles at the three vertices, and let a,b,c be the sides opposite those angles. Acc
Troyanec [42]

Answer:

Step-by-step explanation:

(a)

Consider the following:

A=\frac{\pi}{4}=45°\\\\B=\frac{\pi}{3}=60°

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\frac{b}{a}=\frac{\sinB}{\sin A}
\\\\=\frac{\sin{\frac{\pi}{3}}
}{\sin{\frac{\pi}{4}}}\\\\=\frac{[\frac{\sqrt{3}}{2}]}{\frac{1}{\sqrt{2}}}\\\\=\frac{\sqrt{2}}{2}\times \frac{\sqrt{2}}{1}=\sqrt{\frac{3}{2}}

Again consider,

\frac{b}{a}=\frac{\sin{B}}{\sin{A}}
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Thus, the angle B is function of A is, B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{A}]

Now find \frac{dB}{dA}

Differentiate implicitly the function \sin{B}=\sqrt{\frac{3}{2}}\sin{A} with respect to A to get,

\cos {B}.\frac{dB}{dA}=\sqrt{\frac{3}{2}}\cos A\\\\\frac{dB}{dA}=\sqrt{\frac{3}{2}}.\frac{\cos A}{\cos B}

b)

When A=\frac{\pi}{4},B=\frac{\pi}{3}, the value of \frac{dB}{dA} is,

\frac{dB}{dA}=\sqrt{\frac{3}{2}}.\frac{\cos {\frac{\pi}{4}}}{\cos {\frac{\pi}{3}}}\\\\=\sqrt{\frac{3}{2}}.\frac{\frac{1}{\sqrt{2}}}{\frac{1}{2}}\\\\=\sqrt{3}

c)

In general, the linear approximation at x= a is,

f(x)=f'(x).(x-a)+f(a)

Here the function f(A)=B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{A}]

At A=\frac{\pi}{4}

f(\frac{\pi}{4})=B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{\frac{\pi}{4}}]\\\\=\sin^{-1}[\sqrt{\frac{3}{2}}.\frac{1}{\sqrt{2}}]\\\\\=\sin^{-1}(\frac{\sqrt{2}}{2})\\\\=\frac{\pi}{3}

And,

f'(A)=\frac{dB}{dA}=\sqrt{3} from part b

Therefore, the linear approximation at A=\frac{\pi}{4} is,

f(x)=f'(A).(x-A)+f(A)\\\\=f'(\frac{\pi}{4}).(x-\frac{\pi}{4})+f(\frac{\pi}{4})\\\\=\sqrt{3}.[x-\frac{\pi}{4}]+\frac{\pi}{3}

d)

Use part (c), when A=46°, B is approximately,

B=f(46°)=\sqrt{3}[46°-\frac{\pi}{4}]+\frac{\pi}{3}\\\\=\sqrt{3}(1°)+\frac{\pi}{3}\\\\=61.732°

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3 years ago
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PIT_PIT [208]
I would have to say 85 but thats just a guess.
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