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Dafna1 [17]
3 years ago
6

How many isomers will form in the monochlorination reaction of 2,3−dimethylbutane under radical substitution conditions? What ki

nd(s) of monochlorination products will form (choose all that apply)?
A. 1°
B. 2°
C. 3°
D. allylic

Chemistry
1 answer:
iragen [17]3 years ago
6 0

Answer:

A and C

Explanation:

The <u>monochlorination</u> is a reaction in which we have to add only one Cl to the molecule. In this case we only have <u>two types of carbons</u>. <u>Primary</u> (the methyl groups) and the <u>tertiary</u> (the carbons in the middle).

Therefore we only have  2 type of <u>isomers</u>. The first one in which the Cl would bond to the primary carbons, the <u>primary alkyl halide</u> (1-chloro-2,3-dimethylbutane) and the second one in which the Cl would bond to the tertiary carbons, the <u>tertiary alkyl halide</u> (2-chloro-2,3 -dimethylbutane).

See the figure

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