Ask question

Ask question

All categories

3 years ago

6

How many isomers will form in the monochlorination reaction of 2,3−dimethylbutane under radical substitution conditions? What ki

nd(s) of monochlorination products will form (choose all that apply)?
A. 1°
B. 2°
C. 3°
D. allylic

1 answer:

iragen [17]3 years ago

6 0

Answer:

A and C

Explanation:

The <u>monochlorination</u> is a reaction in which we have to add only one Cl to the molecule. In this case we only have <u>two types of carbons</u>. <u>Primary</u> (the methyl groups) and the <u>tertiary</u> (the carbons in the middle).

Therefore we only have 2 type of <u>isomers</u>. The first one in which the Cl would bond to the primary carbons, the <u>primary alkyl halide</u> (1-chloro-2,3-dimethylbutane) and the second one in which the Cl would bond to the tertiary carbons, the <u>tertiary alkyl halide</u> (2-chloro-2,3 -dimethylbutane).

See the figure

You might be interested in

According to coulomb’s law, what happens to the potential energy of two oppositely charged particles as they get closer together

ValentinkaMS [17]

Answer:

According to coulomb's law their potential energy will increase and the particles will repel each other.

8 0

2 years ago

Read 2 more answers

A quantity that had just a number

Mama L [17]

Answer:

sa

Explanation:

4 0

3 years ago

In the ocean, there are small fish that live in and around the mouths of large sharks. The shark does not harm the fish because

Nikitich [7]

I think the answer is mutualism.

because mutualism means that the two species benefit each other.

7 0

3 years ago

Read 2 more answers

Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).

Pani-rosa [81]

The question is incomplete, here is the complete question:

Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).

Atmospheric Gas Mole Fraction kH mol/(L*atm)

$N_2$ $7.81\times 10^{-1}$ $6.70\times 10^{-4}$

$O_2$ $2.10\times 10^{-1}$ $1.30\times 10^{-3}$

Ar $9.34\times 10^{-3}$ $1.40\times 10^{-3}$

$CO_2$ $3.33\times 10^{-4}$ $3.50\times 10^{-2}$

$CH_4$ $2.00\times 10^{-6}$ $1.40\times 10^{-3}$

$H_2$ $5.00\times 10^{-7}$ $7.80\times 10^{-4}$

<u>Answer:</u> The solubility of hydrogen gas in water at given atmospheric pressure is $1.48\times 10^{-10}M$

<u>Explanation:</u>

To calculate the partial pressure of hydrogen gas, we use the equation given by Raoult's law, which is:

$p_{\text{hydrogen gas}}=p_T\times \chi_{\text{hydrogen gas}}$

where,

$p_A$ = partial pressure of hydrogen gas = ?

$p_T$ = total pressure = 0.380 atm

$\chi_A$ = mole fraction of hydrogen gas = $5.00\times 10^{-7}$

Putting values in above equation, we get:

$p_{\text{hydrogen gas}}=0.380\times 5.00\times 10^{-7}\\\\p_{\text{hydrogen gas}}=1.9\times 10^{-7}atm$

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{H_2}=K_H\times p_{H_2}$

where,

$K_H$ = Henry's constant = $7.80\times 10^{-4}mol/L.atm$

$p_{H_2}$ = partial pressure of hydrogen gas = $1.9\times 10^{-7}atm$

Putting values in above equation, we get:

$C_{H_2}=7.80\times 10^{-4}mol/L.atm\times 1.9\times 10^{-7}atm\\\\C_{CO_2}=1.48\times 10^{-10}M$

Hence, the solubility of hydrogen gas in water at given atmospheric pressure is $1.48\times 10^{-10}M$

4 0

3 years ago

What is the independent variable, and the dependent variable in this?

Doss [256]

Answer:

The salt and sugar as well as the baby power and granulated sugar are the independent variables.

The dependent variable is how it reacts (will it dissolve or not)

Explanation:

5 0

3 years ago

Read 2 more answers