C3H8+3O2--->3CO2+8H
Therefore for every 1:3 there are 3 Carbon dioxides that form. That means find the limiting reactant from the two reactants.
5.5g(1mole C3H8/44.03g of C3H8)=0.1249 moled of C3H8 and if for every one C3H8 we can form three CO2. We can assume 0.3747 miles of CO2 will be produced.
15g of O2(1 mole O2/32g of O2)=0.4685moles O2 and if for every three O2 we can produce three CO2 we may assume a 1:1 ratio.
This means C3H8 will be your limiting reactant. Therefore 0.3747 moles of CO2 will be produced.
0.3747 moles of CO2(48.01 g of CO2/1 mole of CO2)= 17.99 grams of CO2
Answer:
0.40 L
Explanation:
Calculation of the moles of 
as:-
Mass = 51.24 g
Molar mass of = 171.34 g/mol
The formula for the calculation of moles is shown below:
Thus,
Volume = 1.20 L
The expression for the molarity is:
Thus,
Considering
Given that:
So,
<u>The volume of 0.24925M stock solution added = 0.40 L
</u>
1-energy
2- force
3- force
4- force
5- energy
6- energy
The answer is, All of the above
Answer:
what is the formula of rectangle
