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stellarik [79]
3 years ago
11

Consider the following reaction at 298 K: 2H2S(g)+SO2(g)→3S(s, rhombic)+2H2O(g),ΔG∘rxn=−102 kJ Is the reaction more or less spon

taneous under these conditions than under standard conditions? The reaction is
more spontaneous than under standard conditions.
less spontaneous than under standard conditions.
Chemistry
1 answer:
Taya2010 [7]3 years ago
5 0

Answer:

The reaction is  more spontaneous than under standard conditions.

Explanation:

  • For ΔG°rxn, when it is:

negative: the reaction is spontaneous in the forward direction.

zero: the reaction is at equilibrium.

positive: the reaction is non-spontaneous in the forward direction and spontaneous in the reverse direction.

  • Since (ΔG°rxn = − 102 kJ) negative value:

<em>So, the reaction is  more spontaneous than under standard conditions. </em>

<em></em>

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If Ba^{+2} will reacts with N^{-3}, the formula of the compound formed is Ba_3N_2.

<h3>What is an ionic compound?</h3>

Ionic compounds are neutral compounds made up of positively charged ions called cations and negatively charged ions called anions.

Barium is a metal element and Nitrogen is a non-metal element, so they form an ionic compound. To make the formula of an ionic compound, first, we need to see the valence of the atoms, that is, how many electrons it can donate or it has to gain to have 8 electrons in the valence layer (octet rule).

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Writing the ions they must form:

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First came the cation (positive charge), then the anion (negative charge), and the charges must change between them, without the signal, and will inform how many atoms are necessary for which element:

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Hence, If Ba^{+2} will reacts with N^{-3}, the formula of the compound formed is Ba_3N_2.

Learn more about the ionic compound here:

brainly.com/question/9167977

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