<u>ANSWER </u>
and ![y=\frac{1}{4}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B4%7D)
<u>EXPLANATION</u>
Given;
![4x-12y=1](https://tex.z-dn.net/?f=4x-12y%3D1)
and
![6x+4y=4](https://tex.z-dn.net/?f=6x%2B4y%3D4)
The augmented matrix of the two linear equation is given by;
![\left[\begin{array}{ccc}4&-12|&-1\\6\:&\:\:\:4|&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%26-12%7C%26-1%5C%5C6%5C%3A%26%5C%3A%5C%3A%5C%3A4%7C%264%5Cend%7Barray%7D%5Cright%5D)
We now perform row operations;
.
This gives us
![\left[\begin{array}{ccc}1&-3|&\frac{-1}{4}\\6\:&\:\:\:4|&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-3%7C%26%5Cfrac%7B-1%7D%7B4%7D%5C%5C6%5C%3A%26%5C%3A%5C%3A%5C%3A4%7C%264%5Cend%7Barray%7D%5Cright%5D)
![R_2-6R_1 \rightarrow R_2](https://tex.z-dn.net/?f=R_2-6R_1%20%5Crightarrow%20R_2)
![\left[\begin{array}{ccc}1&-3|&\frac{-1}{4}\\0\:&\:\:\:22|&\frac{11}{2}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-3%7C%26%5Cfrac%7B-1%7D%7B4%7D%5C%5C0%5C%3A%26%5C%3A%5C%3A%5C%3A22%7C%26%5Cfrac%7B11%7D%7B2%7D%5Cend%7Barray%7D%5Cright%5D)
![\frac{1}{22}R _2 \rightarrow R_2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B22%7DR%20_2%20%5Crightarrow%20R_2)
![\left[\begin{array}{ccc}1&-3|&\frac{-1}{4}\\0\:&\:\:\:1|&\frac{1}{4}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-3%7C%26%5Cfrac%7B-1%7D%7B4%7D%5C%5C0%5C%3A%26%5C%3A%5C%3A%5C%3A1%7C%26%5Cfrac%7B1%7D%7B4%7D%5Cend%7Barray%7D%5Cright%5D)
![R_1+3R_2 \rightarrow R_1](https://tex.z-dn.net/?f=R_1%2B3R_2%20%5Crightarrow%20R_1)
![\left[\begin{array}{ccc}1&0|&\frac{1}{2}\\0\:&\:\:\:1|&\frac{1}{4}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%7C%26%5Cfrac%7B1%7D%7B2%7D%5C%5C0%5C%3A%26%5C%3A%5C%3A%5C%3A1%7C%26%5Cfrac%7B1%7D%7B4%7D%5Cend%7Barray%7D%5Cright%5D)
Hence
and ![y=\frac{1}{4}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B4%7D)
Answer:
$35
Step-by-step explanation:
If $21 is 60% of the original price, then the original price is ...
21 = 0.60p
21/0.60 = p = 35
The original price is $35.00.
4 1/3 = 13/3 = 1/3 x 13/1 = 4 1/3
Answer:
78.75min
Step-by-step explanation:
t=S/v
105km/80km/hr
=1.3125hr
1.3125hr =78.75min
The product of the factors are;
![\rm(6-3i)(6+3i)=6^2+3^2=36+9 = 45\\\\ (4 -5i)(4 +5i) = 4^2+5^2=16+25=41\\\\(-3+8i)(-3-8i)=(-3)^2+8^2=9+64=73](https://tex.z-dn.net/?f=%5Crm%286-3i%29%286%2B3i%29%3D6%5E2%2B3%5E2%3D36%2B9%20%3D%2045%5C%5C%5C%5C%20%284%20-5i%29%284%20%2B5i%29%20%3D%204%5E2%2B5%5E2%3D16%2B25%3D41%5C%5C%5C%5C%28-3%2B8i%29%28-3-8i%29%3D%28-3%29%5E2%2B8%5E2%3D9%2B64%3D73)
<h3>What is multiplication?</h3>
Multiplication is the process of calculating the product of two or more numbers.
The multiplication of numbers say, ‘a’ and ‘b’, is stated as ‘a multiplied by ‘b’.
The multiplication of the given factors finding by using the following formula.
![\rm (a-ib)(a+ib)=a^2+b^2](https://tex.z-dn.net/?f=%5Crm%20%28a-ib%29%28a%2Bib%29%3Da%5E2%2Bb%5E2)
Applying the formula in the given factors;
![\rm (a-ib)(a+ib)=a^2+b^2\\\\(6-3i)(6+3i)=6^2+3^2=36+9 = 45\\\\ (4 -5i)(4 +5i) = 4^2+5^2=16+25=41\\\\(-3+8i)(-3-8i)=(-3)^2+8^2=9+64=73](https://tex.z-dn.net/?f=%5Crm%20%28a-ib%29%28a%2Bib%29%3Da%5E2%2Bb%5E2%5C%5C%5C%5C%286-3i%29%286%2B3i%29%3D6%5E2%2B3%5E2%3D36%2B9%20%3D%2045%5C%5C%5C%5C%20%284%20-5i%29%284%20%2B5i%29%20%3D%204%5E2%2B5%5E2%3D16%2B25%3D41%5C%5C%5C%5C%28-3%2B8i%29%28-3-8i%29%3D%28-3%29%5E2%2B8%5E2%3D9%2B64%3D73)
To know more about multiplication click the link given below.
brainly.com/question/13691814