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2 years ago

What is the volume of a sphere with a diameter of 5 in? Round your answer to the nearest hundredth of a cubic inch.

Mathematics

1 answer:

Anettt [7]2 years ago

3 0

if the sphere has a diameter of 5, then its radius is half that, or 2.5.

$\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=2.5 \end{cases}\implies V=\cfrac{4\pi (2.5)^3}{3}\implies V=\cfrac{62.5\pi }{3} \\\\\\ V\approx 65.44984694978736\implies V=\stackrel{\textit{rounded up}}{65.45}$

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At his favorite restaurant, Dylan orders a soda with his dinner. The ice in his drink has a mass of 6 g and a volume of 20 cm3.

frez [133]

Answer:

0.3

Step-by-step explanation

The formula to find density is m/v=p

m=mass

v=volume

p=density

All we have to do is plug in 6g and 20cm^3

This will give us 6/20 which simplifies to 3/10

With this you can easily figure out that the decimal for 3/10 is 0.3

So the density of the ice is <u>0.3</u>

<u>Hope this helped!</u>

5 0

1 year ago

L is the midpoint of line segment KM. If KL = 2x - 3 and LM = x + 7. find the value of x.

tatyana61 [14]

Answer:

x = 10

Step-by-step explanation:

Since L is the midpoint

KL = LM

2x-3 = x+7

Subtract x from each side

2x-3-x = x+7-x

x-3 = 7

Add 3 to each side

x-3+3 = 7+3

x = 10

4 0

2 years ago

Read 2 more answers

Help me find the slope

Alex Ar [27]

M= -6/5
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4 0

2 years ago

The length of a rectangle is 7 more than the width. The area is 744 sqaure yards, find the length and width of the rectangle

AVprozaik [17]

Answer:

Length of rectangle is 31 yards and Width is 24 yards.

Given:

The length of a rectangle is 7 more than the width.
The area is 744 sqaure yards

Solution:

Let's assume Width of rectangle be x and Length of rectangle be x + 7 respectively.

Using formula

$\\ \: \: \: \: \pink{ \dashrightarrow \: \: \: \: \sf { \underbrace{Area_{(Rectangle)} = Length × Width }}} \\ \\$

On Substituting the required values, we get;

$\\ \: \: \: \: \dashrightarrow \: \: \: \: \sf (x)(x + 7) = 744 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf {x}^{2} + 7x = 744 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf {x}^{2} + 7x - 744 = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf {x}^{2} + 31x - 24x - 744 = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf x(x + 31) - 24 (x + 31) = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf (x + 31)(x - 24) = 0 \\ \\ \\ \: \: \: \: \dashrightarrow \: \: \: \: \sf x = 24 \: or \: - 31 \\ \\$

As we know that width of the rectangle can't be negative. So x = 24

<u>Hence</u>,

Width of rectangle = x = 24 yards
Length of the rectangle = x + 7 = 31 yards

$\therefore$ Length of rectangle is 31 yards<u> </u>and Width is 24 yards.

8 0

1 year ago

May someone do this for me I don’t under the top part only but you can do the bottom if you feel like it the first gets branlist

UNO [17]

For the first answer it would be y=mc+b

4 0

2 years ago