Question

A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:
1) The year must be divisible by 4

2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400

Some example leap years are 1600, 1712, and 2016.

Write a program that takes in a year and determines whether that year is a leap year.

Ex: If the input is:

1712
the output is:

1712 is a leap year.
Ex: If the input is:

1913
the output is:

1913 is not a leap year.
Your program must define and call the following function. The function should return true if the input year is a leap year and false otherwise.
bool IsLeapYear(int userYear)

Answer 1

Answer:

# include <iostream>

#include<stdio.h>

using namespace std;

bool IsLeapYear(int y)

int main()

{

int y;

cout<<"Enter the Year to check Leap or Not"<<endl;

cin>>y;

IsLeapYear(int y);

getch();

}

bool IsLeapYear(int y)

{

if (y%4==0)

{

   if (y%100==0)

    {

         if (y%400==0 )

         {

          cout<"The year is leap Year";

         }

         else

         {

         cout<<" The year is not Leap Year";

         }

     }

     else

     {

     cout<<"The year is Leap Year" ;

     }

}    

else

{

cout<<"The year is not Leap Year";

}    

}

Explanation:

In this program a function has been defined named as IfLeapYear, to check that whether the entered year is leap year or not. An year taken as integer data type named as y to enter the year to check. If the year is divisible by 4 but not divisible by 100 is the leap year. If the year is divisible by 4, divisible by 100 and also divisible by 400 is the century year and is also the leap year.

To check all the statements, Nested if-else conditions has been used to check multiple requirements of the leap year.

Answer 2

Answer:

Explanation:def is_leap_year(year):

  if(year % 400 == 0):

      return True

  elif year % 100 == 0:

      return False

  elif year%4 == 0:

      return True

  else:

      return False  

if __name__ == '__main__':

  n = int(input())

  if(is_leap_year(n)):

      print(n,"is a leap year.")

  else:

      print(n, "- not a leap year")