We can divide this figure into triangle and trapezoid.
Area of a trapezoid = (1/2)*(base1 +base2)*height = (1/2)(11.75+18)*6.12 = 91.035
Area of a triangle = (1/2)*base*height=(1/2)*12*13.42 = 80.52
Area of the whole figure = 91.035 + 80.52 = 171.555
Answer:
the answer is 4/-1
Step-by-step explanation:
because m= rise/run
Answer:
Solution answer is 
Step-by-step explanation:


then

So
Solution answer is 
Answer:
The answer to the question is
The actual duration of the trip is 8/9 times the normal duration or the bus arrived 1/9 times earlier than it would have at a constant speed of v kph
Step-by-step explanation:
Speed of bus in the first third distance = v kph
Speed of bus for the remaining two thirds = 1.2 v kph
To solve the question, we note that speed = distance/time
therefore time = distance/speed
Let the distance of the destination be D, then
Normal duration at speed v = D/v
Actual duration (D/3)÷v + (2D/3)÷(1.2v) ⇒ (1.2*D/3 + 2D/3)1.2v
=
= (8/9)×D/v
Therefore the actual duration is 8/9 times the normal duration