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Charra [1.4K]
3 years ago
11

Which equation represents exponential decay?

Mathematics
1 answer:
Katarina [22]3 years ago
6 0

Answer:

D, because for every x, the 3 slowly become slower. IF the thing that is being taken to the power of x is less than one it is a decay

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What is the quotient StartFraction 15 p Superscript negative 4 Baseline q Superscript negative 6 Baseline Over negative 20 p Sup
Kitty [74]

Answer:

-\frac{3p^8}{4q^3}

Step-by-step explanation:

\frac{15p^{-4}q^{-6}}{-20p^{-12}q^{-3}}  can be broken down into three fractions, coefficients, powers of p, powers of q.

-\frac{15}{20}\cdot\frac{p^{-4}}{p^{-12}}\cdot\frac{q^{-6}}{q^{-3}}

Simplify the first fraction, then simplify the others by subtracting numerator exponents minus denominator exponents.

-\frac{3}{4} p^{-4-(-12)} q^{-6-(-3)} =-\frac{3}{4} p^8 q^{-3} = \alpha -\frac{3p^8}{4q^3}

8 0
3 years ago
Find the value of this expression if x = 3<br> and y = -1.<br> xy²<br> 5
kap26 [50]

Answer:

<h2><em><u>0.6 = 6/10 = 3/5 is the answer.</u></em></h2>

Step-by-step explanation:

0.6 = 6/10 = 3/5

is the answer

This is because you have to substitute.

Given:

x = 3

y = -1

Unknown:

Final Answer

(x*y^2)/5

((3)(-1*-1)/5

= (3*1)/5

<h2><em><u>= 3/5</u></em></h2><h2><em><u>= 6/10</u></em></h2><h2><em><u>= 0.6</u></em></h2><h2><em><u></u></em></h2>

Hope this helped,

Kavitha

6 0
3 years ago
What is the sum of the geometric sequence -4, 24, -144... if there are 10 terms?
grandymaker [24]

Answer:

34552100

Step-by-step explanation:

Sum=a(r^n-1)/(r-1)=-4*((-6)^n)-1)/(-6-1)=-4*((-6)^10)-1)/(-7)=34552100

Solved by gauthmath.

7 0
3 years ago
HELP LOOK AT THE PIC ( Write the number of the vertices) I FORGOT THIS SINCE YEARS AGO
Kisachek [45]

Answer:

3 vertices

Step-by-step explanation:

Vertices are the "points" of a 2D figure. In this case, we see the 2D figure as a triangle. There are 3 points on the triangle, so there are 3 vertices.

3 0
2 years ago
Find the coefficient of the x^3 in the expansion of (2x-9)^5
il63 [147K]

Use the binomial theorem:

\displaystyle (2x-9)^5 = \sum_{k=0}^5 \binom5k (2x)^{5-k}(-9)^k = \sum_{k=0}^5 \frac{5!}{k!(5-k)!} 2^5 \left(-\frac92\right)^k x^{5-k}

The <em>x</em> ³ terms occurs for 5 - <em>k</em> = 3, or <em>k</em> = 2, and its coefficient would be

\dfrac{5!}{2!(5-2)!} 2^5 \left(-\dfrac92\right)^2 = \boxed{6480}

8 0
3 years ago
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