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pashok25 [27]
3 years ago
14

Answer right and get brainliest and get a thanks ! :-)

Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
7 0
According to me B is the correct answer.
nata0808 [166]3 years ago
5 0
The formula used in this problem is f(t) = f_{1} * r^{t-1}, where r is the common ratio. The common ratio is how you get from one term to the next. In this case, the common ratio is ·4, so from one year, or term, to the next the number of frogs is multiplied by four. This makes the answer B. The number of frogs quadruples every year.
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Evaluate 4x2 +3 when x=5
Molodets [167]

Answer:

103

Step-by-step explanation:

We substitute x with 5:

4(5)^2+3

Solve the exponent first:

5^2 = 25

<em>Note: We are using order of operations (consecutively)</em>

  1. <em>Parentheses </em>
  2. <em>Exponents</em>
  3. <em>Multiplication</em>
  4. <em>Division</em>
  5. <em>Addition </em>
  6. <em>Subtraction</em>

Multiply:

25 * 4 = 100

Add:

100 + 3 = 103

Our answer is 103

<em />

7 0
3 years ago
Read 2 more answers
After knee surgery, your trainer tells you to return to your jogging program slowly. He suggests jogging for 12 minutes each day
frozen [14]
I know you can create an equation to solve this but its been a while since ive done this so im going to slowly write it out.
Day-1=12
2=18
3=24
4=30
5=36
6=42
7=48
8=54
9=60*

n=9
4 0
3 years ago
the perimeter of a rectangle is 48 inches. the ration of the width the length is 3:5, as shown. find the width and the length of
aleksandrvk [35]

Answer:

Width= 18inches Length= 30inches

Step-by-step explanation:

3+5= 8

48/8=6

3*6=18

5*6=30

7 0
3 years ago
Suppose the half-life of a material is 10 days. You have one 1 kg of the material today. How much of the material would you have
boyakko [2]

Answer:

0.50 kg of the material would be left after 10 days.

0.25 kg of the material would be left after 20 days.

Step-by-step explanation:

We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after  10 days and 20 days, respectively.

We will use half life formula.

A=a\cdot(\frac{1}{2})^{\frac{t}{h}}, where,

A = Amount left after t units of time,

a = Initial amount,

t = Time,

h = Half-life.

A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{10}{10}}

A=1\text{ kg}\cdot(\frac{1}{2})^{1}

A=1\text{ kg}\cdot\frac{1}{2}

A=0.5\text{ kg}

Therefore, amount of the material left after 10 days would be 0.5 kg.

A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{20}{10}}

A=1\text{ kg}\cdot(\frac{1}{2})^{2}

A=1\text{ kg}\cdot\frac{1^2}{2^2}

A=1\text{ kg}\cdot\frac{1}{4}

A=0.25\text{ kg}

Therefore, amount of the material left after 20 days would be 0.25 kg.

6 0
3 years ago
Question<br> 9<br> What is the circumference of a circle whose diameter is ?<br> 2
ZanzabumX [31]

6.28 because pi x diameter = circumference.

( diameter = half of a circle)

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
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