(4/(x+4-2))/x+1
4/(x+2)=x/4+1/2
(x/4+1/2)/x+1
x=-2/5
Pretty sure the correct answer is 9/25
Use grid paper to find the median of the data. 9, 7, 2, 4, 3, 5,9,6,8,0,3, 8
Oksanka [162]
Answer:
5.5
Step-by-step explanation:
0,2,3,3,4,5,6,7,8,8,9,9
there are to middle numbers
add then together (5 and 6)
which makes 11
divide 11 by 2
5.5
Answer:
15 ft.
Step-by-step explanation:
I will assume that either both objects are standing straight. We can use similar triangles.
We can see that the side 8 is similar to the side 20, since they are both shadows. Therefore, we can set up an equation:
we can cross multiply and get:
8x=120
solve for x:
x=15
Therefore, the lamppost must be 15 feet tall (unless it fell down but we won't talk about that)
<h2>
Answer:</h2>
y = 5/3x - 9
<h2>
Step-by-step explanation:</h2>
For slope intercept form, you should have the slope and the y intercept.
<em>Slope intercept form is...</em>
y = mx + b
- y being y
- m being slope
- x being x
- b being the y intercept
Moving on:
To find slope, you have to know the rise and run, or the change in y and the change in x.
<em>To find slope...</em>
(-9 - (-14)) / (0 - (-3))
Now, you should be able to calculate that to find that your slope is...
5/3 or 1 2/3
Now, you should be focused on finding your y intercept where the coordinates are (0, b) where b is your y intercept.
<em>Lucky for you, you already have your y intercept being -9 given in the question.</em>
<em />
Finally, to find the slope intercept form! You start off with your main equation for slope intercept form.
y = mx + b
Then you should plug in the numbers you have just found.
<em>Meaning your slope and y intercept...</em>
y = 5/3x - 9
<u />
<u>And I </u><em><u>believe</u></em><u> there is your answer! Tell me if it's wrong please.</u>
, where r is the common ratio. The common ratio is how you get from one term to the next. In this case, the common ratio is ·4, so from one year, or term, to the next the number of frogs is multiplied by four. This makes the answer B. The number of frogs quadruples every year.