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SashulF [63]
2 years ago
7

Dersan went for a run to prepare for a long distance race coming up. From his house, he ran 6 miles directly north, and then 8 m

iles directly west. From there, he ran the diagnoal distance back to his house. How many total miles did Dersan run?​
Mathematics
1 answer:
ella [17]2 years ago
3 0

Answer:

24

Step-by-step explanation:

So, Dersan's path is a right triangle. You have to find the last side. You can use the triples or 6^2+8^2=c^2 but I'll use a triple.

3,4,5.

The last side is 10.

6+8+10=24

hope this helped!

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Graph F(x)=32x+2. Please
olga2289 [7]

Answer:

The required graph is shown below:

Step-by-step explanation:

Consider the provided graph f(x)=32x+2

The above function is a linear function.

We can draw the graph of the linear function with the help of two points.

Substitute x = 0 in f(x)=32x+2

f(0)=32(0)+2

f(0)=2

Hence, the coordinates are (0,2)

Substitute f(x) = 0 in f(x)=32x+2

0=32x+2

32x=-2

x=-0.0625

Hence, the coordinates are (-0.0625,0)

Now join the above points.

The required graph is shown below:

5 0
3 years ago
Read 2 more answers
Help with this question please!
Anton [14]

∠1 and ∠2 are alternate exterior angles where transversal BE crosses parallel lines AC and DF, therefore they are equal. ∠2 and ∠3 are opposite angles of a parallelogram, therefore they are equal.

... ∠1 = ∠2

... 3x -5 = 2x +15 . . . . substitute the given values

... x = 20 . . . . . . . . . . . add 5-2x

The measures of angles 1, 2, and 3 are 2·20+15 = 55 . . . degrees.

5 0
3 years ago
Which set of ordered pairs gives the polygon shown?
makvit [3.9K]
The correct answer is B.

Explanation
Since each interval mark is 1/4 of a unit, we will write this as 0.25.  For the first point, 4 interval marks to the left of the y-axis makes it a negative number; 4(0.25) = 1; this makes the x-coordinate of this point -1.  2 interval marks above the x-axis makes it positive; 2(0.25) = 0.5; this makes the y-coordinate 0.5.  This makes the first ordered pair (-1, 0.5).

The second point is on the y-axis.  This makes the x-coordinate 0.  It is 5 intervals above the x-axis; this makes it positive.  5(0.25) = 1.25 will be the y-coordinate, making the point (0, 1.25).

The third point is 3 intervals to the right of the y-axis; this makes it positive, and 3(0.25)=0.75 for the x-coordinate.  It is 3 intervals below the x-axis; this makes it negative, and 3(0.25) = 0.75, making the y-coordinate -0.75.  This puts the third point at (0.75, -0.75).
7 0
3 years ago
Emily spent half of her weekly allowance playing mini-golf. To earn
myrzilka [38]
Emily’s weekly allowance would be $7.
5 0
3 years ago
a train travels 288km at a uniform speed.if the speed has been 4km per hour more it would have taken one hour less for the same
Lostsunrise [7]

Given:

A train travels 288 km at a uniform speed.

If the speed has been 4 km per hour more it would have taken one hour less for the same journey.

To find:

The initial speed of the train.

Solution:

Let x km/h be the initial speed on the train.

New speed of train = (x+4) km/h

We know that,

Time=\dfrac{Distance}{Speed}

Time taken by the train initially to cover 288 km is \dfrac{288}{x} hours.

New time taken by the train to cover 288 km is \dfrac{288}{x+4} hours.

It is given that If the speed has been 4 km per hour more it would have taken one hour less for the same journey.

\dfrac{288}{x}-\dfrac{288}{x+4}=1

\dfrac{288(x+4)-288x}{x(x+4)}=1

288x+1152-288x=x^2+4x

1152=x^2+4x

0=x^2+4x-1152

Splitting the middle term, we get

x^2+36x-32x-1152=0

x(x+36)-32(x+36)=0

(x+36)(x-32)=0

x=-36,32

We know that the speed cannot be negative. So, the only possible value of x is 32.

Therefore, the speed of the train is 32 km/h.

3 0
2 years ago
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