Answer:
The required graph is shown below:
Step-by-step explanation:
Consider the provided graph 
The above function is a linear function.
We can draw the graph of the linear function with the help of two points.
Substitute x = 0 in 


Hence, the coordinates are (0,2)
Substitute f(x) = 0 in 



Hence, the coordinates are (-0.0625,0)
Now join the above points.
The required graph is shown below:
∠1 and ∠2 are alternate exterior angles where transversal BE crosses parallel lines AC and DF, therefore they are equal. ∠2 and ∠3 are opposite angles of a parallelogram, therefore they are equal.
... ∠1 = ∠2
... 3x -5 = 2x +15 . . . . substitute the given values
... x = 20 . . . . . . . . . . . add 5-2x
The measures of angles 1, 2, and 3 are 2·20+15 = 55 . . . degrees.
The correct answer is B.
Explanation
Since each interval mark is 1/4 of a unit, we will write this as 0.25. For the first point, 4 interval marks to the left of the y-axis makes it a negative number; 4(0.25) = 1; this makes the x-coordinate of this point -1. 2 interval marks above the x-axis makes it positive; 2(0.25) = 0.5; this makes the y-coordinate 0.5. This makes the first ordered pair (-1, 0.5).
The second point is on the y-axis. This makes the x-coordinate 0. It is 5 intervals above the x-axis; this makes it positive. 5(0.25) = 1.25 will be the y-coordinate, making the point (0, 1.25).
The third point is 3 intervals to the right of the y-axis; this makes it positive, and 3(0.25)=0.75 for the x-coordinate. It is 3 intervals below the x-axis; this makes it negative, and 3(0.25) = 0.75, making the y-coordinate -0.75. This puts the third point at (0.75, -0.75).
Emily’s weekly allowance would be $7.
Given:
A train travels 288 km at a uniform speed.
If the speed has been 4 km per hour more it would have taken one hour less for the same journey.
To find:
The initial speed of the train.
Solution:
Let x km/h be the initial speed on the train.
New speed of train = (x+4) km/h
We know that,

Time taken by the train initially to cover 288 km is
hours.
New time taken by the train to cover 288 km is
hours.
It is given that If the speed has been 4 km per hour more it would have taken one hour less for the same journey.





Splitting the middle term, we get




We know that the speed cannot be negative. So, the only possible value of x is 32.
Therefore, the speed of the train is 32 km/h.