Answer:
The actual value is -181/20. Estimate could be -200/20
Step-by-step explanation:
Answer:
Total percent of the room did she paint green = 60%
Step-by-step explanation:
Given - Cheryl painted her living room walls with two different colors. She painted part of the room yellow and another part green. If the surface area of the walls in her room is 720 ft² and she painted 288 ft² yellow.
To find - What percent of the room did she paint green ?
Proof -
Given that,
The surface area of the walls in her room = 720 ft²
Total area painted in yellow color = 288 ft²
So,
Total area painted in green color would be = 720 - 288 = 432 ft²
Now,
Let the total percent green color painted = x
So,
720 × x% = 432
⇒
⇒ x = 
= 60
∴ we get
Total percent of the room did she paint green = 60%
We have the following limit:
(8n2 + 5n + 2) / (3 + 2n)
Evaluating for n = inf we have:
(8 (inf) 2 + 5 (inf) + 2) / (3 + 2 (inf))
(inf) / (inf)
We observe that we have an indetermination, which we must resolve.
Applying L'hopital we have:
(8n2 + 5n + 2) '/ (3 + 2n)'
(16n + 5) / (2)
Evaluating again for n = inf:
(16 (inf) + 5) / (2) = inf
Therefore, the limit tends to infinity.
Answer:
d.limit does not exist
The decay factor for the annual rate of change of - 55 % is 0.45.
A quantity must vary by a specific percentage each time period in order for growth or decay to be exponential.
With the function displayed to the right, you may represent exponential growth or decay.
A(x) = a( 1 + r)ˣ
Where A is the amount after x time periods, a is the initial amount, x is the number of time periods, and r is the rate of change.
Now, we have the annual rate of change as:
r = - 55 % = - 55 / 100 = - 0.55
From the function A(x) = a( 1 + r)ˣ , the corresponding factor is 1 + r.
So, let B = 1 + r
B = 1 + r
B = 1 + (- 0.55)
B = 1 - 0.55
B = 0.45
Now, the value of B is less than 1 therefore, the corresponding decay factor is 0.45.
Learn more about growth and decay factor here:
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