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3 years ago

14

A ball is thrown into the air with an initial upward velocity of 46ft/s. Its height (h) in feet after t seconds is given by the

function h=-16t^2+46t+6. After how many seconds will the ball hit the ground?
A.3
B.4
C.5
D.6

1 answer:

Misha Larkins [42]3 years ago

5 0

The answer is A: 3 feet; this answer can be obtained by finding the zeros of the equation above.

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