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2 years ago

Please somebody I need help

Mathematics

1 answer:

Goshia [24]2 years ago

4 0

Answer:

Step-by-step explanation:

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Here is the next questions brainliest to the first who answer it

qaws [65]

Answer:

Look at the attachment

7 0

2 years ago

How to reduce into simpler terms.?

Sveta_85 [38]

Answer:

The simplest form of the fraction $\frac{45}{100}$ is $\frac{9}{20}$ .

i.e.

$\frac{45}{100}=\frac{9}{20}$

Step-by-step explanation:

Here are some simple observations regarding how to reduce a fraction into simpler terms:

A fraction is reduced to lowest or simplest terms by finding an equivalent fraction in which the numerator and denominator are as small as possible.

In order to reduce a fraction to lowest or simplest terms, divide the numerator and denominator by their (GCF). Note that (GCF) is also called Greatest Common Factor .

So, lets take a sample fraction and reduce into simpler terms.

Considering the fraction

$\frac{45}{100}$

$\mathrm{Find\:a\:common\:factor\:of\:}45\mathrm{\:and\:}100\mathrm{\:in\:order\:to\:cancel\:it\:out}$

$\mathrm{Greatest\:Common\:Divisor\:of\:}45,\:100:\quad 5$

$\mathrm{Factor\:out\:}5\mathrm{\:from\:the\:numerator\:and\:the\:denominator}$

$45=5\cdot \:9\mathrm{,\:\quad }100=5\cdot \:20$

$\frac{45}{100}=\frac{5\cdot \:\:9}{5\cdot \:\:20}$

$\mathrm{Cancel\:the\:common\:factor:}\:5$

$=\frac{9}{20}$

Therefore, the simplest form of the fraction $\frac{45}{100}$ is $\frac{9}{20}$ .

i.e.

$\frac{45}{100}=\frac{9}{20}$

4 0

2 years ago

Nvmm lzodjiofjewkifjf

hoa [83]

Cooooooooooooooooooooooooooooooooooooool

3 0

2 years ago

I’m a bit confused here

alekssr [168]

Y= -x and y= -1/x
Are one-one
y= -x, inverse x= -y
Identify function
hence, inverse of y= -x in y= -x
similarly in the case of y= -1/x
so option (D) I and II, only

7 0

1 year ago

Emanuel has 745 pictures in his phone.His memory is getting full, so he starts deleting 20 pictures every day. Define each varia

BigorU [14]

Let f be the function with variable n, which gives the number of pictures left in the phone after deleting pictures for n-days.

So f(1) gives the number of photos left after 1 day of deleting photos

f(2) gives the number of photos left after 2 days of deleting photos

and so on.

f(1)=745-20
f(2)=745-20-20=745-20*2
f(3)=745-20-20-20=745-20*3

so clearly f(n)=745-20n

Answer:

the algebraic expression is f(n)=745-20n,

where n is the n'th day of deleting photos, and f is the number of photos left after n days of deleting.

7 0

2 years ago