Answer:
≈ 565.5 units²
Step-by-step explanation:
The area (A) of the shaded sector = area of circle × fraction of circle
A = πr² × ← r is the radius
= π × 20² ×
= 400π × 0.45 ≈ 565.5 units²
A paperweight is shaped like a triangular pyramid. The base is an equilateral triangle. Find the surface area of the paperweight
. Thanks soooo much!
1 answer:
Answer:
<h2>8.3 in²</h2>Step-by-step explanation:
We have
three triangles with the base <em>b = 2 in.</em> and the height <em>h₁ = 2.2 in.</em>
one triangle with the base <em>b = 2 in. </em>and the height <em>h₂ = 1.7 in.</em>
The formula of an area of a triangle:
<em>b</em><em> - base</em>
<em>h</em><em> - height</em>
Substitute:
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<h3>Answer: XWY and STR</h3>
I tend to think of parallel lines as train tracks (the metal rail part anyway). Inside the train tracks is the interior region, while outside the train tracks is the exterior region. Alternate exterior angles are found here. Specifically they are angles that are on opposite or alternate sides of the transversal cut.
Both pairs of alternate exterior angles are shown in the diagram below. They are color coded to help show how they pair up and which are congruent.
A thing to notice: choices B, C, and D all have point W as the vertex of the angles. This means that the angles somehow touch or are adjacent in some way due to this shared vertex point. However, alternate exterior angles never touch because parallel lines never do so either. We can rule out choices B,C,D from this reasoning alone. We cannot have both alternate exterior angles on the same exterior side of the train tracks. Both sides must be accounted for.