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Zinaida [17]
4 years ago
13

Which substance is most likely to be miscible with water? (hint: determine which molecule is polar)?

Chemistry
1 answer:
Allushta [10]4 years ago
5 0
The question is missing the choices and these are CHCl3, CF4, CS2 or Br2.A polar molecule is one in which the atoms are organized such that one end of the molecule has a positive charge and the conflicting end has the opposite or negative charge. So in the given choices above, the most polar one CHCl3 this actually the only polar one in the choices. The explanation behind this is it has the same shape as CCl4 molecule, but one of the Chlorine atoms has been substituted by a Hydrogen atom. We know that Hydrogen has a weaker electronegativity in contrast to Chlorine, so electron density along the h-c bond is dragged away from the Hydrogen and in the direction of the ccl3 fragment, resulting in a polar molecule.
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what is the concentration in ppm of a solution which is prepared by dissolving in 15mg of nacl in 200ml water
bezimeni [28]

Answer:

Explanation:

In weight/volume (w/v) terms,

   1 ppm = 1g m-3 = 1 mg L-1 = 1 μg mL-1

200 mL = 0.2 L

15 / 0.2 mg L-1 =75 ppm

6 0
3 years ago
HELP!!! DUE TONIGHT!!
IRINA_888 [86]

Answer:

K I will attempt

Explanation:

a)

O_2_{(g)}+ 2H_2_{(g)} => 2H_2O_{(l)}\\

b)

1 : 2 : 2 (I don't know if this is what the question wants but it is what I would answer)

c)

Hydrogen because it requires 2 moles of H2 to react with 1 mole of O2

d)

24 moles of water. Look at stoichiometric coefficient. 2:2 means 24 moles you get 24 moles

e)

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f)

First, let's find out how many moles of water we can get. Since O2 is the limiting reactant, and O2:H2O ratio is 1:2, we will get 4 moles of H2O. Then, we can multiply 4 by Avogadro's number which is 6.022*10^{23} to get the number of molecules. We get: 2.41 * 10^24 molecules of water.

6 0
3 years ago
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HELP!! Please answer!
zloy xaker [14]

Answer: the % is 99.73 and the mass is 40.986

Explanation:

5 0
3 years ago
The molar heat of fusion for water is 6.01 kJ/mol. How much energy must be added to a 75.0-g block of ice at 0°C to change it to
andreyandreev [35.5K]
Answer is: 25,06 kJ of energy must be added to a 75 g block of ice.
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T(H₂O) = 0°C.
m(H₂O) = 75 g.
n(H₂O) = m(H₂O) ÷ M(H₂O).
n(H₂O) = 75 g ÷ 18 g/mol.
n(H₂O) = 4,17 mol.
Q = ΔHfusion(H₂O) · n(H₂O)
Q = 6,01 kJ/mol · 4,17 mol
Q = 25,06 kJ.
7 0
3 years ago
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The emission spectrums are known for the elements below. Line spectra for boron, lithium, hydrogen, helium, potassium and unknow
Montano1993 [528]

Answer:

E

Explanation:

8 0
3 years ago
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