Which substance is most likely to be miscible with water? (hint: determine which molecule is polar)?

1 answer:

5 0

The question is missing the choices and these are CHCl3, CF4, CS2 or Br2.A polar molecule is one in which the atoms are organized such that one end of the molecule has a positive charge and the conflicting end has the opposite or negative charge. So in the given choices above, the most polar one CHCl3 this actually the only polar one in the choices. The explanation behind this is it has the same shape as CCl4 molecule, but one of the Chlorine atoms has been substituted by a Hydrogen atom. We know that Hydrogen has a weaker electronegativity in contrast to Chlorine, so electron density along the h-c bond is dragged away from the Hydrogen and in the direction of the ccl3 fragment, resulting in a polar molecule.

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811.68 J of energy are used on a 95g chunk of unknown metal. Calculate the resulting temperature change if the specific heat of

Ivan

Answer:

16 °C

Explanation:

Step 1: Given data

Provided heat (Q): 811.68 J

Mass of the metal (m): 95 g

Specific heat capacity of the metal (c): 0.534 J/g.°C

Step 2: Calculate the temperature change (ΔT) experienced by the metal

We will use the following expression.

Q = c × m × ΔT

ΔT = Q/c × m

ΔT = 811.68 J/(0.534 J/g.°C) × 95 g = 16 °C

6 0

2 years ago

Se ha añadido un evaporador para una alimentación de 11500 kg/dia de zumo de pomelo de forma que evapore 3000 kg/dia de agua por

mamaluj [8]

Answer:

37 %.

Explanation:

¡Hola!

En este caso, para el problema descrito, conocemos la corriente de entrada y la de salida del agua, por lo que podemos obtener el flujo de la corriente que contiene el zumo a la salida una vez el agua fue evaporada:

$F_{sol}=11500kg/dia-3000kg/dia=8500 kg/dia$

Luego, por medio de un balance de zumo de limón en el evaporador en el cual la cantidad que entra es igual a la que sale con sus respectivas concentraciones:

$x_z^{entra}*11500kg/dia=x_z^{sale}*8500kg/dia$