Answer:
the volume of CHCI3 = 7.87 ml
the volume of CHBr3 = 12.13 ml
Explanation:
From the given information:
We all know that 1 g/cm^3 = 1 g/ml
The density of boron = 2.34 g/ml
The Volume of the liquid mixture = 20 ml
Recall that:
Density = mass/volume
Mass = Density × Volume
Mass = 2.34 g/ml × 20 ml
Mass = 46.8 g
Suppose the volume of CHCI3 be Y and the Volume of CHBr3 be 20 - Y
Then :
Y (1.492) + 20-Y(2.890) = 46.8
1.492Y + 57.8 - 2.890Y = 46.8
- 1.398 Y = -11
Y = -11/ - 1.398
Y = 7.87 ml
Therefore, the volume of CHCI3 7.87 ml
the volume of CHBr3 = 20 - Y
= 20 - 7.87
= 12.13 ml
Answer:
1. The heat energy in Joules is 5280.22J
2. The heat energy in calories is 1261.4 calories
Explanation:
Step 1:
Data obtained from the question.
The following data were obtained from the question:
Mass of water (M) = 74.2 g
Initial temperature (T1) = 24°C
Final temperature (T2) = 41°C
Change in temperature (ΔT) = T2 - T1 = 41 - 24 = 17°C
Heat energy (Q) =?
Recall:
Specific heat capacity of water = 4.186 J/g°C
Step 2:
Determination of the energy in Joules.
This is illustrated below:
Q = MCΔT
Q = 74.2 x 4.186 x 17
Q = 5280.22J
Step 3:
Conversion of the heat energy in Joules to calories. This is illustrated below:
4.186 J = 1 calorie
Therefore, 5280.22J = 5280.22/4.186 = 1261.4 calories
