Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
The answer is yes she incorrectly graphed using the points (-2,4) instead of the point (4,-2). This is the answer because if you solve the equation given you should get y=-3/5x+2/5 so a and e will be wrong and if you plug one of the points in you will give a untrue statement so its not d so you are left with b and c so you plug in the end request and you get a true statement with b equaling -2 if you plug in 4 in for x
Step-by-step explanation:
14x+10+2x
16x+10. Answer 1
5x+3x+10+8x
16x+10. Answer 2
So, both Answers are same, So the expressions are equivalent...
Step-by-step explanation:
44 month old
12 months=1 year
44÷12=3 2/3
3 2/3 years
