Answer:
30m
Step-by-step explanation:
<em>Since we are not told what to look for, we can find the maximum height reached by the rocket</em>
Given the rocket's flight approximately modeled by the equation
h(t) = - 12t ^ 2 + 36t + 3
At maximum height dh/dt = 0
dh/dt = --24t + 36
0 = -24t + 36
24t = 36
t= 36/24
t = 1.5s
Get the max height
h(1.5) = - 12 (1.5)^ 2 + 36(1.5) + 3
h(1.5) = - 12(2.25) + 54 + 3
h(1.5) = -27 + 57
h(1.5) = 30m
Hence the maximum height reached by the rocket is 30m
Answer:
Inequality form: -3 
x 0
Interval Notation: [-3, 0]
Step-by-step explanation:
Isolate the variable by dividing each side by the factors.
Answer:
you will use the SOHCAHTOA METHOD IF ITS A TRIANGLE. Not sure
Answer: A, B, C
Step-by-step explanation:
Substituting into point-slope form, we get 
and 
. Rearranging this into slope-intercept form,
