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aksik [14]
3 years ago
14

Quickkk?!! For each equation, determine whether it is linear.

Mathematics
2 answers:
Scrat [10]3 years ago
5 0

Answer:

a. Linear

b. Linear

c. Non-linear

d. Linear

Furkat [3]3 years ago
5 0

Answer:

a. Linear

b. Linear

c. Not Linear

d. Linear

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If m<1=28 and<1 and <2 from a right angle. Find m<2
weeeeeb [17]
28+ x = 90
-28 -28
x = 62°

7 0
3 years ago
-10.7+-3.5 <br> I don’t understand yes I know I am dumb :D
lesya [120]

Answer: -14.2 hoped this help kiddo

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
40 is the sum of 15 and Craig's savings.<br> Use the variable c to represent Craig's savings.
andrew-mc [135]
40=15+c

Hope it helps
8 0
3 years ago
Read 2 more answers
Anyone know how to do this? If so plz help
bekas [8.4K]

NOTES:

Use the equation y = mx + b where m is the unit rate and b is the one-time flat fee

1. Answer:

\begin {array}{c||c|c|c|c}x&0&1&2&3\\ y&70.00&70.20&70.40&70.60\\\end{array}

<u>Step-by-step explanation:</u>

coffee maker costs $70 - this is a one-time flat fee

it costs $0.20 per cup of coffee - this is the unit rate

y = 0.20x + 70

y = 0.20(0) + 70   →   y = 0.00 + 70   →   y = 70.00

y = 0.20(1) + 70   →   y = 0.20 + 70    →   y = 70.20

y = 0.20(2) + 70   →   y = 0.40 + 70   →   y = 70.40

y = 0.20(3) + 70   →   y = 0.60 + 70   →   y = 70.40

*******************************************************************************

2. Answer:

\begin {array}{c||c|c|c|c}x&1&2&3&4\\ y&4.50&6.00&7.50&9.00\\\end{array}

<u>Step-by-step explanation:</u>

shoes costs $3.00 - this is a one-time flat fee

it costs $1.50 per game of bowling - this is the unit rate

y = 1.50x + 3.00

y = 1.50(1) + 3.00  →    y = 1.50 + 3.00   →   y = 4.50

y = 1.50(2) + 3.00  →   y = 3.00 + 3.00   →   y = 6.00

y = 1.50(3) + 3.00  →   y = 4.50 + 3.00   →   y = 7.50

y = 1.50(4) + 3.00  →   y = 6.00 + 3.00   →   y = 9.00

*******************************************************************************

3. Answer: Negative

<u>Step-by-step explanation:</u>

As the x-values increase, the y-values decrease.  Opposite directions results in a negative slope.

*******************************************************************************

4. Answer: Gym A → y = 20x + 50    Gym B → y = 25x + 30

<u>Step-by-step explanation:</u>

Use the slope formula: m = \dfrac{y_2-y_1}{x_2-x_1}.  Then choose ONE of the points and input the point (x₁, y₁) and slope (m) into the Point-Slope formula: y - y₁ = m(x - x₁) and solve for y.

Gym A: (x₁, y₁) = (1, 70) and (x₂, y₂) = (2, 90)

m=\dfrac{90-70}{2-1} = \dfrac{20}{1} = 20

y - 70 = 20(x - 1)

y - 70 = 20x - 20

y        = 20x + 50

Gym B: (x₁, y₁) = (1, 55) and (x₂, y₂) = (2, 80)

m=\dfrac{80-55}{2-1} = \dfrac{25}{1} = 25

y - 55 = 25(x - 1)

y - 55 = 25x - 25

y        = 25x + 30


5 0
3 years ago
Solve the proportion
mario62 [17]

Answer:

\boxed{\sf x = 5}

Step-by-step explanation:

\sf Solve  \: for  \: x  \: over  \: the  \: real \:  numbers:  \\ \sf \implies  \frac{2}{x - 3}   =  \frac{5}{x}  \\  \\  \sf Take  \: the \:  reciprocal  \: of  \: both \:  sides:  \\ \sf \implies  \frac{x - 3}{2}  =  \frac{x}{5}  \\  \\  \sf Expand  \: out \:  terms \:  of \:  the \:  left  \: hand \:  side:  \\  \\ \sf \implies \frac{x}{2}  -  \frac{3}{2}  =  \frac{x}{5}  \\  \\  \sf Subtract \:  \frac{x}{5}   -  \frac{3}{2}  \: from  \: both  \: sides: \\  \sf \implies \frac{x}{2}  -  \frac{3}{2} - ( \frac{x}{5}   -  \frac{3}{2} ) =  \frac{x}{5} - ( \frac{x}{5}  -  \frac{3}{2} ) \\  \\  \sf \implies \frac{x}{2}  -  \frac{3}{2} -  \frac{x}{5}    +   \frac{3}{2} =  \frac{x}{5} -  \frac{x}{5}  +  \frac{3}{2}  \\  \\  \sf \frac{x}{5}  -  \frac{x}{5}  = 0 :  \\  \sf \implies \frac{x}{2}  -  \frac{x}{5}  -  \frac{3}{2}  +  \frac{3}{2}  =  \frac{3}{2}  \\  \\  \sf  \frac{3}{2}   -   \frac{3}{2}   = 0:  \\  \sf \implies \frac{x}{2}  -  \frac{x}{5}  =  \frac{3}{2}   \\  \\ \sf \frac{x}{2}  -  \frac{x}{5} =  \frac{5x - 2x}{10}  =  \frac{3x}{10} :  \\   \sf \implies \frac{3x}{10}  =  \frac{3}{2}   \\  \\ \sf Multiply \:  both  \: sides \:  by \:  \frac{10}{3}  : \\   \sf \implies \frac{3x}{10}  \times  \frac{10}{3}  =  \frac{3}{2 }  \times  \frac{10}{3}   \\  \\ \sf \frac{3x}{10}  \times  \frac{10}{3}  =   \cancel{\frac{3}{10} } \times( x) \times  \cancel{ \frac{10}{3} } = x :  \\  \sf \implies x =  \frac{3}{2}  \times  \frac{10}{3} \\  \\   \sf  \frac{3}{2}  \times  \frac{10}{3}  = \cancel{ \frac{3}{2} }  \times \cancel{ \frac{3}{2} }  \times 5 :   \\ \sf \implies x = 5

8 0
3 years ago
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