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sleet_krkn [62]
3 years ago
8

An unknown element has two isotopes. The first isotope has a mass of 68.926 amu and an abundance of 60.108%. The second isotope

has a mass of 70,925 amu and an abundance
of 39.892%. Calculate the average atomic mass AND identify the element.
Chemistry
2 answers:
In-s [12.5K]3 years ago
5 0

M
r
(
G
a
)
=
69.7231
to 4 decimal places
.
Explanation:
To find the average atomic mass (
A
r
) of an element, given the percentage rarities of its isotopes, simply multiply each isotope's
A
r
by its percentage that is expressed as a decimal and total the results. We can carry this out in a single line of working:
M
r
(
Ga
)
=
(
68.9256
⋅
0.60108
)
+
(
70.9247
⋅
0.39892
)

M
r
(
Ga
)
=
69.7231
to 4 decimal places

Similarly, you could input the percentages normally and then divide by
100
:
M
r
(
Ga
)
=
(
68.9256
⋅
60.108
)
+
(
70.9247
⋅
39.892
)
100

M
r
(
Ga
)
=
69.7231
to 4 decimal places

Notice that the answers are the same. Also observe that the answer is closer to 69 than it is to 71, which makes sense since gallium-69 makes up a greater proportion of gallium in the universe (
~
60
%
) than gallium-71 does (
~
30
%
)
wel3 years ago
4 0

Answer:

69.72344108

Gallium

Explanation:

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