Where in the mitochondria does the electron transport chain occur

Green plants absorb sunlight to power photosynthesis, the chemical synthesis of food from water and carbon dioxide. The compound

Kamila [148]

Answer:

$698 \ THz$

Explanation:

Data provided as per the question below:-

Wavelength = 430.nm

The computation of the frequency of the light is shown below:-

Frequency = Velocity of light ÷ Wavelength

The Velocity of light = $= {3.0 \times 10^8 \ m/s}$

Wavelength = 430 nm = $4.30 \times 10^-^7$ m

Frequency = $\frac{3.0 \times 10^8 \ m/s}{4.30 \times 10^-^7}$

$= 6.98 \times 10^1^4 \ hz$

$= 6.98 \times 10^2 \ Thz$

= $698 \ THz$

Therefore for determining the frequency we simply applied the above formula.

4 0

3 years ago

.

konstantin123 [22]

Answer:

the temperature of the star

Explanation:

The color of stars usually indicates the temperature of the star.

A star that is relatively cold usually shows a typical red color.

The hottest stars have a blue color.

These star colors have been used by astronomers to determine their temperature.
A broad spectrum between blue, the hottest color, and red the coldest is used.
Class O stars are usually the blue colored ones
Class M is the coldest with red color

8 0

3 years ago

The vapor pressure of benzene at 298 K is 94.4 mm of Hg. The standard molar Gibbs free energy of formation of liquid benzene at

horsena [70]

Answer:

ΔfG°(C₆H₆(g)) = 129.7kJ/mol

Explanation:

Bringing out the parameters mentioned in the question;

Vapor pressure = 94.4 mm of Hg

The vaporization reaction is given as;

C₆H₆(l) ⇄ C₆H₆(g)

Equilibrium in terms of activities is given by:

K = a(C₆H₆(g)) / a(C₆H₆(l))

Activity of pure substances is one:

a(C₆H₆(l)) = 1

Assuming ideal gas phase activity equals partial pressure divided by total pressure. At standard conditions

K = p(C₆H₆(g)) / p°

Where p° = 1atm = 760mmHg standard pressure

We now have;

K = 94mmHg / 760mmHg = 0.12421

Gibbs free energy is given as;

ΔG = - R·T·ln(K)

where R = gas constant = 8.314472J/molK

So ΔG° of vaporization of benzene is:

ΔvG° = - 8.314472 · 298.15 · ln(0.12421)

ΔvG° = 5171J/mol = 5.2kJ/mol

Gibbs free energy change of reaction = Gibbs free energy of formation of products - Gibbs free energy of formation of reactants:

ΔvG° = ΔfG°(C₆H₆(g)) - ΔfG°(C₆H₆(l))

Hence:

ΔfG°(C₆H₆(g)) = ΔvG°+ ΔfG°(C₆H₆(l))

ΔfG°(C₆H₆(g)) = 5.2kJ/mol + 124.5kJ/mol

ΔfG°(C₆H₆(g)) = 129.7kJ/mol

6 0

4 years ago

If 190dm of hydrogen gas collected at 20°c and 760mmHg .Calculate it's volume at stp (standard pressure=760mmHg

Andrei [34K]

Answer:

177.1 L

Explanation:

The excersise can be solved, by the Ideal Gases Law.

P . V = n . R . T

In first step we need to determine the moles of gas:

We convert T° from, C° to K → 20°C + 273 = 293K

We convert P from mmHg to atm → 760 mmHg = 1atm

1Dm³ = 1L → 190L

We replace: 190 L . 1 atm = n . 0.082 . 293K

(190L.atm) / 0.082 . 293K = 7.91 moles.

We replace equation at STP conditions (1 atm and 273K)

V = (n . R .T) / P

V = (7.91 mol . 0.082 . 273K) / 1atm = 177.1 L

We can also make a rule of three:

At STP conditions 1 mol of gas occupies 22.4L

Then, 7.91 moles will be contained at (7.91 . 22.4) /1 = 177.1L

3 0

3 years ago

Why is it illegal to manufacture fireworks without a license

victus00 [196]

Illegal Explosives. Illegal explosives associated with the fireworks season are inherently dangerous because of their composition and unpredictability. Homemade explosives can pose a particular risk for injury because the people making them often lack knowledge and experience in manufacturing fireworks.

3 0

3 years ago