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Kryger [21]
3 years ago
12

A motorcycle travel at 6.0 m/s. After 3.0 second, the motorcycle travel at 15.0 m/s. Which of the following was the average acce

leration of the motorcycle?​
Chemistry
1 answer:
Lerok [7]3 years ago
7 0

Hello!

\large\boxed{a = 3m/s^{2}}

Use the following equation to solve for the average acceleration of the motorcycle:

a = \frac{v_{f}-v_{i}}{t}

Plug in the given final, initial velocities, and the time:

a = \frac{15-6}{3}\\\\a = \frac{9}{3}\\\\a = 3m/s^{2}

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Atomic number is less than 11
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What type of cells does the human reproductive system contain?
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A chemist prepares a solution of sodium thiosulfate (Na2S203) by measuring out 110.g of sodium thiosulfate into a 350. mL volume
forsale [732]

Answer:

1.99 M

Explanation:

The molar mass of sodium thiosulfate (solute) is 158.11 g/mol. The moles corresponding to 110 grams are:

110 g × (1 mol/158.11 g) = 0.696 mol

The volume of solution is 350 mL = 0.350 L.

The molarity of sodium thiosulfate is:

M = moles of solute / liters of solution

M = 0.696 mol / 0.350 L

M = 1.99 M

5 0
3 years ago
Calculate the radius ratio for NaBr if the ionic radii of Na + and Br − are 102 pm and 196 pm , respectively. radius ratio: Base
Fudgin [204]

Answer : The expected coordination number of NaBr is, 6.

Explanation :

Cation-anion radius ratio : It is defined as the ratio of the ionic radius of the cation to the ionic radius of the anion in a cation-anion compound.

This is represented by,

\frac{r_{cation}}{r_{anion}}

When the radius ratio is greater than 0.155, then the compound will be stable.

Now we have to determine the radius ration for NaBr.

Given:

Radius of cation, Na^+ = 102 pm

Radius of cation, Br^- = 196 pm

\frac{r_{cation}}{r_{anion}}=\frac{102}{196}=0.520

As per question, the radius of cation-anion ratio is between 0.414-0.732. So, the coordination number of NaBr will be, 6.

The relation between radius ratio and coordination number are shown below.

Therefore, the expected coordination number of NaBr is, 6.

8 0
3 years ago
What is the mass of 0.5 moles of NaCl
Debora [2.8K]

Answer:

29.25g

Explanation:

m=0.5×(23+35.5)

6 0
2 years ago
Read 2 more answers
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