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DiKsa [7]
2 years ago
12

Multiply. 8 1/2 -2 2/3

Mathematics
2 answers:
MrRissso [65]2 years ago
5 0

Answer: -\frac{68}{3} or -22\ 2/3

Step-by-step explanation:

To solve this problem you must:

- Convert the mixed numbers to fractions, as following:

8\ 1/2=\frac{((8*2)+1)}{2}=\frac{17}{2}

2\ 2/3=\frac{((3(2)+2)}{3}=\frac{8}{3}

- Multiply both fractions. Mutilply the numerators and the denominators:

(\frac{17}{2})(-\frac{8}{3})=-\frac{136}{6}

- Simplify. Therefore, you obtain that the answer is:

-\frac{68}{3} or -22\ 2/3

zavuch27 [327]2 years ago
4 0
<h2>Answer:</h2>

<u>Answer is </u><u>5 5/6.</u>

<h2> Explanation:</h2>

For solution check the attached picture below.

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What is the value of X?
bearhunter [10]
Let's solve this problem step-by-step.

STEP-BY-STEP SOLUTION:

Let's first establish that the shape is a triangle meaning that the following formula is applicable as displayed below:

Angle sum of a triangle = 180°

As well as this, the shape is an equilateral triangle meaning that each angle of the triangle is equivalent in value. Also, the following formula is also applicable as displayed below:

Each angle of an equilateral triangle = the same value

Therefore:

Each angle of an equilateral triangle = angle sum of a triangle ÷ no. of angles in a triangle = 180° ÷ 3 = 60°

Based on this, the following is applicable:

2x - 4 = 60°

2x = 60 + 4

2x = 64

x = 64 / 2

x = 32°

ANSWER:

Therefore, the answer is:

The value of ( x ) is 32°


Please mark as brainliest if you found this helpful! :)
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8 0
3 years ago
A hockey puck has a diameter of 3 inches and rolls on its edge for 24 rotations. How far did it roll before falling flat?
scoundrel [369]

Find the circumference of the puck using circumference = pi x diameter

Circumference = 3.14 x 3 = 9.42 inches.

For every rotation the puck would travel 9.42 inches.

Now multiply y by 24 rotations:

9.42 x 24 = 226.08 inches.

Answer: 226.08 inches

4 0
3 years ago
Explain: How would you solve the equation? Place the steps below in the correct order.
nirvana33 [79]

use the distributive property

combine alike terms

add the negative number to the other side

combine alike terms

then divide on both sides to get the variable by itself

8 0
3 years ago
The question is:
saul85 [17]
f(x) = \sqrt{x+1} \\ y = \sqrt{x+1} \ or \ y^2 = x+1 \ or \ x = y^2 - 1 \\ Therefore, \ f^{-1}(x)=x^2 - 1

(fof^{-1})(a) = f(f^{-1}(a))=f(a^2-1) \\ =\sqrt{a^2-1+1}=\sqrt{a^2}=a \\  \\ (f^{-1}of)(a)=f^{-1}(f(a))=f^{-1}(\sqrt{a+1})= \\ (\sqrt{a+1})^2-1 = a+1-1 = a

Therefore, (fof^{-1})(a) = (f^{-1}of)(a) = a

8 0
2 years ago
Continue each pattern with the next two numbers
kobusy [5.1K]
The 18th sequence is - 41
7 0
3 years ago
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