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3 years ago

Please Help!! The answer is your own opinion!

2 answers:

7 0

I found nothing difficult in factoring as calculator would do the work while graphing is too troublesome for a few marks worth of question
i prefer factoring

Ainat [17]3 years ago

4 0

The only thing I found difficult in factoring was the difference of two squares, but factoring was easy because you can plug it all into the calculator. Graphing is easy because you just type the equations in and find whatever you need to find via 2nd trace

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Spencer has a rectangular garden. The length and width are both odd numbers and the perimeter is 16 feet. What can be the area o

vovikov84 [41]

Area of rectangle = length x width

Perimeter of rectangle = 2 x (length + width)

Now we know that perimeter of rectangle = 16

2(length + width) = 16

Length + width = 16/2

Length + width = 8

Now the value of length and width is that if we add both values we have the answer 8.

So, here are some possible values of length and width and also that length and width are odd numbers;

Odd numbers are = 1,3,5,7,….

7 + 1 = 8

5 + 3 = 8

So, either length is 7 and with is 1 or length is 5 and width is 3

So area of rectangle = 7 x 1 = 7 or 5 x 3 = 15

Thus, the possible values of area of rectangle are 7 ft² and 15 ft².

5 0

4 years ago

This year, a small business had a total revenue of $81,900 . If this is 26% more than their total revenue the previous year, wha

Tems11 [23]

$65000 was the total revenue for the previous year.
65000 x .26 = 16900
65000 + 16900 = 81,900

8 0

3 years ago

Read 2 more answers

Which statements accurately describe the function f(x) = 3(StartRoot 18 EndRoot) Superscript x? Select three options. The domain

Studentka2010 [4]

Answer:

The domain is all real numbers.

The initial value is 3

The simplified base is $9\sqrt{2}$

Step-by-step explanation:

The given function is $f(x)=3(\sqrt{18})^x$ .

To find the initial value, we put x=0 into the function:

$f(0)=3(\sqrt{18})^0$ .

$f(0)=3(1)=3$ .

The initial value is actually 3.

The given function is an exponential function, therefore the domain is all real numbers.

The range of this function refers to all values of y for which the function is defined.

The line y=0, is the horizontal asymptote.

The range is $y\:>\:0$

The simplified base is $3\sqrt{18}=3\sqrt{9\times2}$ .

$3\sqrt{18}=3\sqrt{9}\times\sqrt{2}$

$3\sqrt{18}=3\times3\times\sqrt{2}$

$3\sqrt{18}=9\sqrt{2}$

4 0

3 years ago

Read 2 more answers

un repartidor de refrescos entrego 90 cajas en tres pedidos. En le primero dejo el doble que en el segundo, y en el segundo, el

GenaCL600 [577]

Answer:

Step-by-step explanation:

Djjirjtti

5 0

3 years ago

Mr. Sanchez’s class sold fruit pies for $1.55 each and Mr. Kelly’s class sold bottles of fruit juice for $1.40 each. Together, t

hoa [83]

Answer:

Mr. Sanchez's class sold 28 fruit pies and Mr. Kelly's class sold 32 bottles of fruit juice.

Step-by-step explanation:

Let x be the number of fruit pies sold and y be the number of bottles of fruit juice sold.

Together, the classes sold 60 items, so

x + y = 60

Mr. Sanchez’s class sold fruit pies for $1.55 each, so x fruit pies cost $1.55x.

Mr. Kelly’s class sold bottles of fruit juice for $1.40 each, so y bottles of fruit juice cost $1.40y.

Together, the classes earned $88.20 for their school, so

1.55x + 1.40y = 88.20.

You get the system of two equations:

$\left\{\begin{array}{l}x+y=60\\ \\1.55x+1.40y=88.20\end{array}\right.$

From the first equation:

$x=60-y$

Substitute it into the second equation:

$1.55(60-y)+1.40y=88.20\\ \\93-1.55y+1.4y=88.2\\ \\-0.15y=88.2-93\\ \\-0.15y=-4.8\\ \\0.15y=4.8\\ \\15y=480\\ \\y=32\\ \\x=60-32=28$

Mr. Sanchez's class sold 28 fruit pies and Mr. Kelly's class sold 32 bottles of fruit juice.

8 0

3 years ago