How do you answer (-1) to the power of 5?

Help me plz with this giving brainless to the right answer

Soloha48 [4]

Answer:whats the question

Explanation:(pls dont report me as soon as u tell me the question i will edit my answer and answer correctly)

4 0

3 years ago

Let T: P2 → P3 be the transformation that maps a polynomial p(t) into the polynomial (t-2)p(t).

lutik1710 [3]

(a) Applying T to p(t) = 2 - t + t ² gives

T ( p(t) ) = (t - 2) (2 - t + t ²) = -4 + 4t - 3t ² + t ³

(b) T is a linear transformation if for any p(t) and q(t) in P₂ and complex scalars a and b, the image of any linear combination of p and q is equal to the linear combination of the images of p and q. In other words,

T ( a p(t) + b q(t) ) = a T ( p(t) ) + b T ( q(t) )

Let

p(t) = α₀ + α₁ t + α₂ t ²

q(t) = β₀ + β₁ t + β₂ t ²

Compute the images of p and q :

T ( p(t) ) = (t - 2) (α₀ + α₁ t + α₂ t ²)

… = -2α₀ + (α₀ - 2α₁) t + (α₁ - 2α₂) t ² + α₂ t ³

Similarly,

T ( q(t) ) = -2β₀ + (β₀ - 2β₁) t + (β₁ - 2β₂) t ² + β₂ t ³

Then

a T ( p(t) ) + b T ( q(t) ) = a (-2α₀ + (α₀ - 2α₁) t + (α₁ - 2α₂) t ² + α₂ t ³) + b (-2β₀ + (β₀ - 2β₁) t + (β₁ - 2β₂) t ² + β₂ t ³)

… = c₀ + c₁ t + c₂ t ² + c₃ t ³

where

c₀ = -2 (a α₀ + b β₀)

c₁ = a (α₀ - 2α₁) + b (β₀ - 2β₁)

c₂ = a (α₁ - 2α₂) + b (β₁ - 2β₂)

c₃ = a α₂ + b β₂

Computing the image of a p(t) + b q(t) would give the same result; just multiply it by t - 2 and expand. This establishes that T is indeed linear.

(c) Find the image of each vector in the basis for P₂ :

T (1) = (t - 2) × 1 = t - 2

T (t ) = (t - 2) t = t ² - 2t

T (t ²) = (t - 2) t ² = t ³ - 2t ²

Then

$T=\begin{bmatrix}-2&0&0\\1&-2&0\\0&1&-2\\0&0&1\end{bmatrix}$

4 0

3 years ago

8b²+7b factorize it i want the explantion also pll help

tekilochka [14]

So you would but a b on the outside and on the inside, you would put 8b because b x 8b makes b^2. Then, you would put +7 for the 7b and then close the brackets and thats your answer b(8b+7)

5 0

4 years ago

Read 2 more answers

Can someone answer this please

Gwar [14]

Answer:

The coordinates of point P are (1, -1)

Step-by-step explanation:

If the point (x, y) reflected about the x-axis, then its image is (x, -y)

To find the image of a point reflected about the x-axis change the sign of its y-coordinate

The rule is R x-axis → (x, -y)

If the point (x, y) reflected about the y-axis, then its image is (-x, y)

To find the image of a point reflected about the y-axis change the sign of its x-coordinate

The rule is R y-axis → (-x, y)

→ Assume that the coordinates of point P are (x, y)

∵ The coordinates of point P are (x, y)

∵ The rule of the reflection is R y-axis (P)

∴ Its image = (-x, y)

∵ The image = (-1, -1)

→ Equate the two images

∴ (-x, y) = (-1, -1)

∴ -x = -1

→ Divide both sides by -1

∴ x = 1

∵ y = -1

∴ The coordinates of point P are (1, -1)

4 0

3 years ago

Samira ran around a park loop that was one-third mile long. she ran around the loop nine times. samira says she ran 9/3 miles. h

Alexeev081 [22]

1/3 mile x 9 times = 3

They both are 9/3 simplifies to 3

4 0

3 years ago