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Nastasia [14]
4 years ago
5

Rewrite 3/8 and 5/14 to have a common denominator

Mathematics
1 answer:
Natasha2012 [34]4 years ago
5 0
8 and 14 have a common factor of 56 so == 7/56 and 20/56
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Oliver drove the first 90 miles of his journey in 1.5 hours and the remaining 120 in 3 hours. What was the average speed on the
ikadub [295]
Creo que la respuesta es C. No soy bueno con el inglés, pero eso es lo que pienso. Lo siento si está mal.
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3 years ago
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Sierra downloaded 123 pictures from her cell phone to her computer. These pictures used 246 megabytes of space on her computer.
defon

Answer:

94 Mb

Step-by-step explanation:

123x=246Mb---->x=2Mb

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3 years ago
What are two fractions equal to 2/5?
ycow [4]
4/10 and 6/15. I got these answers by multiplying the numerator and denominator by 2 to get 4/10 and then multiplied the numerator and denominator by 3 to get 6/15. If you were to simplify these fractions completely, you would be left with the original fraction, 2/5.
8 0
4 years ago
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The degree measure of angle a is 135°. which expression below is equivalent to the radian measure of angle a?
Kazeer [188]

It is given that \angle a=135^{\circ}.

Now, know that in 180 degrees there are \pi radians. This can be written as:

180^{\circ}=\pi radians

\therefore 1^{\circ}=\frac{\pi}{180} radians (dividing both sides by 180)

Thus, to find the measure of the given angle of 135^{\circ} in radians, we will have to multiply the above equation by 135. Thus, we get:

135^{\circ}=\frac{\pi}{180}\times 135 radians

135^{\circ}\approx2.356 radians

Thus, equivalent to the radian measure of angle a is 2.356


7 0
4 years ago
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A function f is defined by f(x) = 1 + 6x + x2 + 6x3 + x4 + ⋯ that is, its coefficients are c2n = 1 and c2n + 1 = 6 for all n ≥ 0
Alenkinab [10]

From the odd-degree terms, take out one copy and rewrite the series as

1+6x+x^2+6x^3+\cdots=(1+x+x^2+x^3+\cdots)+5x+5x^3+\cdots

1+6x+x^2+6x^3+\cdots=(1+x+x^2+x^3+\cdots)+5x(1+x^2+\cdots)

Then if |<em>x</em>| < 1, we can condense this to

\displaystyle\sum_{n=0}^\infty x^n+5x\sum_{n=0}^\infty x^{2n}=\frac1{1-x}+\frac{5x}{1-x^2}=\frac{1+6x}{1-x^2}

Since the series we invoked here converge on -1 < <em>x</em> < 1, so does this one.

4 0
3 years ago
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