Answer: 4π cm or 12.56 cm
Step-by-step explanation: To find the circumference of this circle, start with the formula for the circumference of a circle which is C = 2πr.
Since the radius is 2 centimeters, we can
plug in 2 centimeters for <em>r</em> in the formula.
So we have (2)(π)(2 cm) which is equal to 4π cm.
So the circumference of this circle is 4π cm.
Remember that π is approximately equal to 22/7 or 3.14 so we can estimate the value of the circumference by plugging in 3.14 for π.
So we have (4)(3.14) which is equal to 12.56.
So the circumference of the circle is
approximately equal to 12.56 cm.
Answer:
use formula length × width ×height
Step-by-step explanation:
plug in what they have given you
Explanation:
The question requires that we round the given number to Ten-thousand
To do so, we will have to write the place values of the numbers first
Next, we find the digits before the Ten-thousand digits and then approximate the value
One of the principles to use is that
numbers from 0 to 4 are rounded to 0
while numbers from 5 to 9 are rounded to 1
In our case, The thousand digit is 0, so we round down to 0, then we add to the Ten-thousand digits and convert each of the numbers before the Ten-thousand digits to 0
Thus, we will have
![1,370,000](https://tex.z-dn.net/?f=1%2C370%2C000)
Hence, the answer is 1,370,000
The measure of the supplementary angle is 148 degrees.
Hope this helps!
Answer:
Step-by-step explanation:
Domain is all the x's and range is all the y's. There's no reason why you couldn't pop any x into the given equation and calculate it and get a number out. So literally ANY x can be used and found on this graph. So the domain is all real numbers, one of the first two answers is going to be the right one. Now, the range is all the y's on the graph. The problem says that the parabola opens down, which means it has a highest point. There is no graph above that point. That's the point (-1, 16). So 16 is the highest y-value you can find on the graph. All the rest of the y's are smaller. The range is all the y's such that the y's are 16 and smaller...in math that's written {y | y <= 16} So the second answer is the right one.