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3 years ago

BRAINLIEST ASAP! PLEASE HELP ME :)

Mathematics

1 answer:

masha68 [24]3 years ago

5 0

Answer:

○ $\displaystyle 0 + 2kπ$

Explanation:

See above explanation

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What is the sum of the first 11 terms of the arithmetic series in which a1 = 12 and d = 5?. (Points : 1). 38. . 549. . 143. . 2

Marina CMI [18]

First we will find the 11th term
an = a1 + (n-1) * d
a11 = 12 + (11 - 1) * 5
a11 = 12 + 10 * 5
a11 = 12 + 50
a11 = 62

now we use the sum formula...
Sn = (n (a1 + an)) / 2
S11 = (11 (12 + 62)) / 2
S11 = (11 (74)) / 2
S11 = 814/2
S11 = 407

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2 years ago

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I really don't understand why this question was deleted its not bad I don't know how to explain it

nalin [4]

Answer:

Step-by-step explanation:

Because it is a square root

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3 years ago

Suppose r(t)=costi+sintj+3tk represents the position of a particle on a helix, where z is the height of the particle above the g

Ilia_Sergeevich [38]

a. The $\vec k$ component tells you the particle's height:

$3t=16\implies t=\dfrac{16}3$

b. The particle's velocity is obtained by differentiating its position function:

$\vec v(t)=\dfrac{\mathrm d\vec r(t)}{\mathrm dt}=-\sin t\,\vec\imath+\cos t\,\vec\jmath+3\,\vec k$

so that its velocity at time $t=\frac{16}3$ is

$\vec v\left(\dfrac{16}3\right)=-\sin\dfrac{16}3\,\vec\imath+\cos\dfrac{16}3\,\vec\jmath+3\,\vec k$

c. The tangent to $\vec r(t)$ at $t=\frac{16}3$ is

$\vec T(t)=\vec r\left(\dfrac{16}3\right)+\vec v\left(\dfrac{16}3\right)t$

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3 years ago

How do I solve these equations

Sever21 [200]

You need to know the properties of each function.
Tan is opposite (y) over adjacent (x). Sin>0 means that sin is positive, therefore, it is located on either quadrant 1 or 2. Tan=4/3 so it is located in quadrant 1.
The side of the triangle must be Adjacent=3 opposite=4 and hypotenuse=5
Now, you are asked to find the half angle of Cos which is
$\sqrt{\frac{1+cos}{2} }$
By following the formula, cos=3/5 then:
$\sqrt{ \frac{1- \frac{3}{5} }{2} }$ Multiply everything (inside the square $\sqrt{ \frac{5+3}{10} }$ root) by 5
$\frac{2 \sqrt{2} }{ \sqrt{10} }$
$\frac{2 \sqrt{20} }{10}$ Then just simplify
$\frac{ \sqrt{20} }{5}$ The answer is Square root of 20 over 5

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3 years ago

22 1 point If f (x) = 7– 41, what is f (-10)?

Anettt [7]

Answer:

f(x)+41 f(-10)=7

Step-by-step explanation:

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3 years ago