1. Let's call the number of carter school: "x" and "y" the number of alternative school. Then, you have that:
- T<span>he number of charter schools is 4 less than twice the number of alternative schools.
</span> - T<span>here are 48 charter schools in the country.
2. So, you have:
x=2y-4 (i)
x=48 (ii)
3. Then, when you substitute x=48 into the equation (i), you obtain:
</span>
x=2y-4
<span> 48=2y-4
4. Now, you must clear "y, as below:
48+4=2y
2y=52
y=52/2
y=26
</span><span>
How many alternative schools are in the county?
</span><span>
The answer is: There are 26 alternative schools.</span>
Answer:
![P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68](https://tex.z-dn.net/?f=P%28B%27%20%5Ccup%20A%27%29%20%3D%20P%28%28A%20%5Ccap%20B%29%27%29%20%3D%201-P%28A%20%5Ccap%20B%29%3D%201-0.32%3D0.68)
See explanation below.
Step-by-step explanation:
For this case we define first some notation:
A= A new training program will increase customer satisfaction ratings
B= The training program can be kept within the original budget allocation
And for these two events we have defined the following probabilities
![P(A) = 0.8, P(B) = 0.2](https://tex.z-dn.net/?f=%20P%28A%29%20%3D%200.8%2C%20P%28B%29%20%3D%200.2)
We are assuming that the two events are independent so then we have the following propert:
![P(A \cap B ) = P(A) * P(B)](https://tex.z-dn.net/?f=%20P%28A%20%5Ccap%20B%20%29%20%3D%20P%28A%29%20%2A%20P%28B%29)
And we want to find the probability that the cost of the training program is not kept within budget or the training program will not increase the customer ratings so then if we use symbols we want to find:
![P(B' \cup A')](https://tex.z-dn.net/?f=%20P%28B%27%20%5Ccup%20A%27%29%20)
And using the De Morgan laws we know that:
![(A \cap B)' = A' \cup B'](https://tex.z-dn.net/?f=%20%28A%20%5Ccap%20B%29%27%20%3D%20A%27%20%5Ccup%20B%27)
So then we can write the probability like this:
![P(B' \cup A') = P((A \cap B)')](https://tex.z-dn.net/?f=%20P%28B%27%20%5Ccup%20A%27%29%20%3D%20P%28%28A%20%5Ccap%20B%29%27%29)
And using the complement rule we can do this:
![P(B' \cup A') = P((A \cap B)')= 1-P(A \cap B)](https://tex.z-dn.net/?f=%20P%28B%27%20%5Ccup%20A%27%29%20%3D%20P%28%28A%20%5Ccap%20B%29%27%29%3D%201-P%28A%20%5Ccap%20B%29)
Since A and B are independent we have:
![P(A \cap B )=P(A)*P(B) =(0.8*0.4) =0.32](https://tex.z-dn.net/?f=%20P%28A%20%5Ccap%20B%20%29%3DP%28A%29%2AP%28B%29%20%3D%280.8%2A0.4%29%20%3D0.32)
And then our final answer would be:
![P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68](https://tex.z-dn.net/?f=P%28B%27%20%5Ccup%20A%27%29%20%3D%20P%28%28A%20%5Ccap%20B%29%27%29%20%3D%201-P%28A%20%5Ccap%20B%29%3D%201-0.32%3D0.68)
27; The first stack is 3 x 3 (= 9). You then multiply 9 by 3 (for each of the 3 stacks). Basically, 3 x 3 x 3.
Answer:
Area of composite figure = 216 cm²
Hence, option A is correct.
Step-by-step explanation:
The composite figure consists of two figures.
1) Rectangle
2) Right-angled Triangle
We need to determine the area of the composite figure, so we need to find the area of an individual figure.
Determining the area of the rectangle:
Given
Length l = 14 cm
Width w = 12 cm
Using the formula to determine the area of the rectangle:
A = wl
substituting l = 14 and w = 12
A = (12)(14)
A = 168 cm²
Determining the area of the right-triangle:
Given
Base b = 8 cm
Height h = 12 cm
Using the formula to determine the area of the right-triangle:
A = 1/2 × b × h
A = 1/2 × 8 × 12
A = 4 × 12
A = 48 cm²
Thus, the area of the figure is:
Area of composite figure = Rectangle Area + Right-triangle Area
= 168 cm² + 48 cm²
= 216 cm²
Therefore,
Area of composite figure = 216 cm²
Hence, option A is correct.
Answer:
$138
Step-by-step explanation:
We can first turn the words into a mathematical equation by substituting words with the information we have:
Total earning - ( Price of three books)
$180 - (Price of one book x 3)
$180 - ($14 x 3)
Finally, after we have created the mathematical equation, we solve it!
$180 - ($14 x 3)
$180 - $42
$138