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emmainna [20.7K]
3 years ago
8

We need help solving problem 5.

Mathematics
1 answer:
maksim [4K]3 years ago
8 0

can I get a better picture? please

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I need to know how to describe the parts of the expression (3x-2)
zalisa [80]

Answer:

If the arrow is pointing to the -2, that’s the constant.

If the arrow is pointing at x, that’s the variable.

If the arrow is pointing at 3, that’s the coefficient.

5 0
3 years ago
Read 2 more answers
The owner of a fish market has an assistant who has determined that the weights of catfish are normally distributed, with mean o
prohojiy [21]

Answer:

The percentage of samples of 4 fish will have sample means between 3.0 and 4.0 pounds is 66.87%

Step-by-step explanation:

For a normal random variable with mean Mu = 3.2 and standard deviation sd = 0.8 there is a distribution of the sample mean (MX) for samples of size 4, given by:

Z = (MX - Mu) / sqrt (sd ^ 2 / n) = (MX - 3.2) / sqrt (0.64 / 4) = (MX - 3.2) / 0.4

For a sample mean of 3.0, Z = (3 - 3.2) / 0.4 = -0.5

For a sample mean of 3.0, Z = (4 - 3.2) / 0.4 = 2.0

P (3.2 <MX <4) = P (-0.5 < Z <2.0) = 0.6687.

The percentage of samples of 4 fish will have sample means between 3.0 and 4.0 pounds is 66.87%

6 0
3 years ago
Please help, I will mark brainliest!
4vir4ik [10]
4
Put the smol 7 next to it !!

8 0
2 years ago
The Tigers, a football team, must gain 10 yards in the next four plays to keep possession of the ball . The Tigers lose 12 yards
mestny [16]

No because They lose 12 sand that puts them at -12. Then they gain 5 which puts them at -7 and then they lose 8 which puts them at -15. Please mark as brainliest

5 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
olga nikolaevna [1]
<h3>Answer:   1.15</h3>

==============================================================

Work Shown:

QR = 73

QP = 55

PR = x

Pythagorean Theorem

a^2 + b^2 = c^2

(QP)^2 + (PR)^2 = (QR)^2

(55)^2 + (x)^2 = (73)^2

3025 + x^2 = 5329

x^2 = 5329-3025

x^2 = 2304

x = sqrt(2304)

x = 48

PR = 48

----------

tan(angle) = opposite/adjacent

tan(R) = QP/PR

tan(R) = 55/48

tan(R) = 1.1458333 approximately

tan(R) = 1.15

8 0
3 years ago
Read 2 more answers
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