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The probability that Rebecka selects a terrier and Aaron selects a retriever is 10/121
<h3>How to determine the probability?</h3>
The distribution of the puppies is given as:
4 poodles, 5 terriers, and 2 retrievers
The probability of selecting a terrier is;
P(terrier) = 5/11
The probability of selecting a retriever is;
P(retriever) = 2/11
The required probability is
P = 5/11 * 2/11
Evaluate
P = 10/121
Hence, the probability that Rebecka selects a terrier and Aaron selects a retriever is 10/121
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Answer:
<em>The answer resides in the explanation.</em>
<em>Pls rate as brainliest </em>
Step-by-step explanation:
The predicted useful life of a brand A cutting tool when the speed is 45 meters per minute is 1.2 to 5.5 hours.
The predicted useful life of a brand B cutting tool when the speed is 45 meters per minute is 3.4 to 5.4 hours.
The prediction interval for brand A is larger than the prediction interval for brand B because the estimated standard error of y^ is different for the two intervals.
The prediction intervals are both larger than the corresponding confidence intervals.
The standard error for the estimated mean value of y is smaller than the standard error for the predicted value of y.
The predicted useful life of a brand A cutting tool that is operated at 100 meters per minute is -0.59 hours
The actual predicted useful life of a brand A cutting tool when the speed is 100 meters per minute is 0.0 to 2.3 hours.
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C) 1/25 for every 1 it goes up 25. therefore 1/25! hope I helped!!! brainliest would be much appreciated because I am trying to rank up!!!
