Easy question help please

The sum of nine times a number, and 4, is equal to eight times the number.

pishuonlain [190]

Answer:

-4

Step-by-step explanation:

Let's put this in math notation. We can call the number x:

9x+4=8x

Subtract 8x from both sides:

x+4=0

Subtract 4 from both sides:

x=-4

4 0

2 years ago

Read 2 more answers

The leg of a right triangle is 2 units and the hypotenuse is 5 units. What is the length, in units, of the other leg of the tria

AVprozaik [17]

For this question, we have to use the Pythagorean theory since we're dealing with a right triangle.

a² + b² = c²

We're given the value of the hypotenuse and a leg, therefore we're looking for the value of the other leg.

Now let's plug in the given data into our equation.

2² + b² = 5²
4 + b² = 25
b² = 25 - 4
b² = 21
√b² = √21 = b

The correct answer is B) √21

8 0

3 years ago

F(x) = V2x<br> g(x) = V18x<br> Find (f .g)(x). Assume x2 0.

Nina [5.8K]

Answer:

fog(x) is D = 6 $\sqrt{x}$

Step-by-step explanation:

I. square all value, so f(x) is 2x then g(x) is 18x

II. Replace x.value in f(x) with g(x).value = 2(18x)

III. If x is 1, 2(18*1) will be 36; find root, so answer is 6

If x is 2, 2(18*2) will be 72; find root, so answer is 6 $\sqrt{2}$

Hope it help, sorry if I'm done it wrong, but I think it's gonna be the right answer. :)

3 0

3 years ago

Mechanic charges $55 for the first hour and $50 for each additional hour how much does he charge if it takes him in four hours t

VMariaS [17]

Answer:

440$

Step-by-step explanation:

55 x 4=220

50 x 4=200

440$

I hope this is correct if not im sorry

8 0

2 years ago

Read 2 more answers

A sample of 18 small bags of the same brand of candies was selected. Assume that the population distribution of bag weights is n

ki77a [65]

Answer:

a)

i. x=- - - - - -

ii. o=- - - - - -

iii. Sx=- - - - -

b) The random variable X signifies the weights of the bags of candies which are selected at random.

c) The statistics variable X is a measure on a sample that is used as an estimate of the population mean.X is the mean weight of the 16 bags of candies that were selected.

d) The distribution needed for this problem is normal distribution with parameters because the population standard deviation is known.

N(X, o/ $\sqrt{n}$ )

So, the distribution is

N(2, 0.12/ $\sqrt{16}$ )

e)

i. The 90% confidence interval for the population mean weight of the candies is 1.9589 , 2.0411

iii. The error bound is 0.0411

f)

i. The 98% confidence interval for the population mean weight of the candies is 1.9418 , 2.0582

iii. The error bound is 0.0582

g) The difference in the confidence intervals in part (f) and part (e) is of the level of confidence. The change is, the change in the area being calculated for the normal distribution. Therefore, the larger confidence level results in larger area and larger interval.

Hence the interval in part is larger than the one in part (e).

h) The interval in part (f) signifies that with 98% confidence that the population mean weight of the bag of candies lies between 1.942 ounce and 2.058 ounce.

Step-by-step explanation:

a)

i. x=- - - - - -

ii. o=- - - - - -

iii. Sx=- - - - -

b) The random variable X signifies the weights of the bags of candies which are selected at random.

c) The statistics variable X is a measure on a sample that is used as an estimate of the population mean.X is the mean weight of the 16 bags of candies that were selected.

d) The distribution needed for this problem is normal distribution with parameters because the population standard deviation is known.

N(X, o/ $\sqrt{n}$ )

So, the distribution is

N(2, 0.12/ $\sqrt{16}$ )

e)

i. The 90% confidence interval for the population mean weight of the candies is 1.9589 , 2.0411

iii. The error bound is 0.0411

f)

i. The 98% confidence interval for the population mean weight of the candies is 1.9418 , 2.0582

iii. The error bound is 0.0582

g) The difference in the confidence intervals in part (f) and part (e) is of the level of confidence. The change is, the change in the area being calculated for the normal distribution. Therefore, the larger confidence level results in larger area and larger interval.

Hence the interval in part is larger than the one in part (e).

h) The interval in part (f) signifies that with 98% confidence that the population mean weight of the bag of candies lies between 1.942 ounce and 2.058 ounce.

5 0

3 years ago