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NISA [10]
3 years ago
10

I need help with these plzzz

Mathematics
1 answer:
Sonja [21]3 years ago
3 0

Answer:

Third on

Step-by-step explanation:

(the ratios are both identical)

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Solve the system of linear equations y= 2x -3Y= x + 6
Alja [10]

Answer:

x=9, y=15. (9, 15).

Step-by-step explanation:

y=2x-3

y=x+6

----------

2x-3=x+6

2x-x-3=6

x-3=6

x=6+3

x=9

y=9+6=15

7 0
2 years ago
CAN I PLEASE NOT HAVE TO DO A FREE TRIAL
kakasveta [241]

Answer: u don’t have to do it at all like u don’t have to do anything on brainly

Step-by-step explanation:

8 0
2 years ago
4/5a - 8 = a + 2 solve for a
balandron [24]

Answer:

-32/5

Find more steps at S_Y_M_B_O_L_A_B

7 0
2 years ago
Read 2 more answers
I need help on what to say
garik1379 [7]
Part A: 75 and 8 are both coefficients in this case since both numbers are in front of a variable. D and W are two variables in this expression since they are letters that represent unknown numbers. 25 is the constant since that number does not change.

Part B: If Javier works for 5 days and installs 48 windows, he earns $784.
75d+8w+25
75(5)+8(48)+25
375+384+25
784

Part C: If Javier receives $40 for snacks instead of 25, the constant would change since 25 was the constant to begin with. The rest of the expression would stay the same. The new expression would look like this: 75d+8w+40.

I hope this was helpful.
7 0
4 years ago
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Find the tenth term of the expansion (x+ y)¹³
Anon25 [30]

Answer:

715x^4y^9

Step-by-step explanation:

Given

(x + y)^{13

Required

Determine the 10th term

Using binomial expansion, we have:

(a + b)^n = ^nC_0a^nb^0 + ^nC_1a^{n-1}b^1 + ^nC_2a^{n-2}b^2 +.....+^nC_na^{0}b^n

For, the 10th term. n = 9

So, we have:

(a + b)^n = ^nC_{9}a^{n-9}b^{9

(x + y)^{13} = ^{13}C_{9}x^{13-9}y^9

(x + y)^{13} = ^{13}C_{9}x^4y^9

Apply combination formula

(x + y)^{13} = \frac{13!}{(13-9)!9!}x^4y^9

(x + y)^{13} = \frac{13!}{4!9!}x^4y^9

(x + y)^{13} = \frac{13*12*11*10*9!}{4!9!}x^4y^9

(x + y)^{13} = \frac{13*12*11*10}{4!}x^4y^9

(x + y)^{13} = \frac{13*12*11*10}{4*3*2*1}x^4y^9

(x + y)^{13} = \frac{17160}{24}x^4y^9

(x + y)^{13} = 715x^4y^9

Hence, the 10th term is 715x^4y^9

3 0
3 years ago
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