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Soloha48 [4]
3 years ago
5

PLEASE HELP FAST! 50 POINTS!

Mathematics
1 answer:
Vladimir [108]3 years ago
4 0

Answer:

A. 0

B. there are many options for this but just some examples are

120, 150, 180, 210, 240, 270, 300, 330, 360, 390

Step-by-step explanation:

the rest of the options are

420, 450, 480, 510, 540, 570, 600, 630, 660, 690,

720, 750, 780, 810, 840, 870, 900, 930, 960, 990.

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PLEASE HELP ME BRANNIEST
Nastasia [14]

The solution is the x intercept

In this case the x- intercept is

(3,-2) or B


8 0
3 years ago
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I’m confused and I need help
Jlenok [28]
I believe it is 64 because 8 times 8 is 64
3 0
4 years ago
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Evaluate 7d, when d = 9 please!
Bond [772]

Answer:

63

Step-by-step explanation:

When d=9, the equation should be 7 times 9 because you need to plug 9 in. Therefore, 7 times 9 is 63! I hope that helps!

5 0
3 years ago
. Find the area of the regular dodecagon inscribed in a circle if one vertex is at (3, 0).
devlian [24]

Answer:

Area of the regular dodecagon inscribed in a circle will be 27 square units.

Step-by-step explanation:

A regular dodecagon is the structure has twelve sides and 12 isosceles triangles inscribed in a circle as shown in the figure attached.

Since angle formed at the center by a polygon = \frac{360}{n}

Therefore, angle at the center of a dodecagon = \frac{360}{12} = 30°

Since one of it's vertex is (3, 0) therefore, one side of the triangle formed or radius of the circle = 3 units

Now area of a small triangle = \frac{1}{2}.(a).(b).sin\theta

where a and b are the sides of the triangle and θ is the angle between them.

Now area of the small triangle = \frac{1}{2}.(3).(3).sin30

= \frac{9}{4}

Area of dodecagon = 12×area of the small triangle

= 12×\frac{9}{4}

= 27 unit²

Therefore, area of the regular octagon is 27 square unit.

4 0
3 years ago
Solve for n.<br> 11(n-1)+35=3n
kotykmax [81]

Answer:

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

Solution

= − 3

11−11+35=3 11+24=3

11+24=311n+24=3n11n+24=3n11+24−24=3−24 1

4 0
3 years ago
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