Answer:
No, I do not agree with them. Both are wrong.
Step-by-step explanation:
For a shape or figure to be considered a scaled copy of another, the length of all the segments of scaled copy must be equal to the length of all corresponding segments of the original figure multiplied by the same scale factor.
By examining the scaled copies B, C, and D, we would conclude that only D can be referred to as a scaled copy of D, because all the segments are exactly twice the corresponding segments of A. C and B do not have all its segment scaled in the same proportion.
Therefore, we cannot agree with Priya, nor Tyler. They are both wrong.
Answer:
The original height of the tree is 18 m.
Step-by-step explanation:
Please see attached photo for explanation.
From the diagram, we shall determine the value of 'x'. This can be obtained by using the pythagoras theory as follow:
x² = 5² + 12²
x² = 25 + 144
x² = 169
Take the square root of both side
x = √169
x = 13 m
Finally, we shall determine the original height of the tree. This can be obtained as follow.
From the question given above, the tree was broken from a height of 5 m from the ground which form a right angle triangle with x being the Hypothenus as illustrated in the diagram.
Thus, the original height of the will be the sum of 5 and x i.e
Height = 5 + x
x = 13 m
Height = 5 + 13
Height = 18 m
Therefore, the original height of the tree is 18 m.
<span>The basic idea is that you form a parallelogram with those two vectors as the two different side lengths
another way to see it: start at the tip of one vector and move in the same direction as the other vector (and the same length as the other vector)
</span><span>With any parallelogram, the adjacent angles are supplementary</span>
180-52-20= 108 degrees
Answer:
Try using estimation.
Make sure you don't start with the y-axis first.
I don't think they really want an exact answer though. You could try using a ruler if there's one on your phone but I still think estimation is okay.
Step-by-step explanation:
Look how close the point is to 1 on the x-axis and how close it is to 2 on the x-axis then chose what you think fits.
One possible equation for this quadratic would be
y=(x-4)²-1. This is vertex form: y=a(x-h)²+k, where (h, k) is the vertex.
However, this is not the only possible equation. There could be multiple values for a, in front of the parentheses, that we don't know about from the information we are given.
We can also write this equation in standard form (y=ax²+bx+c). First write the squared binomial as the product of two binomials:
y=(x-4)(x-4)-1
Multiply the binomials:
y=x*x-4*x-4*x-4(-4)-1
= x²-4x-4x--16-1
= x²-8x+16-1
= x²-8x+15
Again, this would change depending on what the value of a is in the functoin.
