Answer:
a)
b)
Step-by-step explanation:
Previous concepts
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.
The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).
Solution to the problem
For this case we have defined the following random variable Y="number of moving violations for which the individual was cited during the last 3 years. "
And we have the distribution for Y given:
y 0 1 2 3
P(y) 0.6 0.2 0.15 0.15
Part a
For this case the expected value is given by:
And if we replace the values given we have:
Part b
For this case we have defined a new random variable representing a subcharge, and we want to find the expected amount for this random variable, using properties of expected value we have:
And we can find on this way:
And if we replace the values given we have:
And then replacing we got:
Answer:
10,454,400 sec
Step-by-step explanation:
1Day=24hr
1hr=60min
1min=60sec
121 days=121*24*60*60=10,454,400sec
1/5 = 0.2 = 20%
100% - 20% - 10% = 70%
He left 70%
<33
Answer:
A=$21930.52
Step-by-step explanation:
Given data
Principal =44000
Time =5years
Rate of depreciation =13%
The expression for the depreciation is
A=P(1-r)^t
Substitute
A=44000(1-0.13)^5
A=44000(0.87)^5
A=44000*0.4984209207
A=21930.52