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ANSWER
The height of the larger cone is 3cm
EXPLANATION
Since the two cones are similar we can use the scale factor to determine the height of the larger cone.
It was given that, the volume of the larger cone is 27 cm³ and the volume of the smaller cone is 8 cm³.
The scale factor for the volume is
The scale factor for the length is
![k = \sqrt[3]{ \frac{27}{8} }](https://tex.z-dn.net/?f=k%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B27%7D%7B8%7D%20%7D%20)
To find the height of the larger cone, we multiply by
The height of the larger cone is 3cm
EXPLANATION
Since the two cones are similar we can use the scale factor to determine the height of the larger cone.
It was given that, the volume of the larger cone is 27 cm³ and the volume of the smaller cone is 8 cm³.
The scale factor for the volume is
The scale factor for the length is
To find the height of the larger cone, we multiply by
<u>Solution-</u>
Given that,
In the parallelogram PQRS has PQ=RS=8 cm and diagonal QS= 10 cm.
Then considering ΔPQT and ΔSTF,
1- ∠FTS ≅ ∠PTQ ( ∵ These two are vertical angles)
2- ∠TFS ≅ ∠TPQ ( ∵ These two are alternate interior angles)
3- ∠TSF ≅ ∠TQP ( ∵ These two are also alternate interior angles)
<em>If the corresponding angles of two triangles are congruent, then they are said to be similar and the corresponding sides are in proportion.</em>
∴ ΔFTS ∼ ΔPTQ, so corresponding side lengths are in proportion.
As QS = TQ + TS = 10 (given)
If TS is x, then TQ will be 10-x. Then putting these values in the equation
∴ So TS = 3.85 cm and TQ is 10-3.85 = 6.15 cm
Consider the equation
1) First row of the table
Set x=0 and solve as follows:
The answer is y=20 and the pair x-y is (0,20)
2) Second row
Set x=1 and solve, as follows:
The answers are y=10 and (1,10)
3) Third row.
Set y=0 and solve as follows:
The answers are x=2 and (2,0)
Answer:
480 mm³
Step-by-step explanation:
The volume (V) of a pyramid is
V = area of base × height, hence
V = × 96 × 15 = 32 × 15 = 480