Given:
Seven times the smaller of two consecutive even integers is the same as -300 minus 4 times the larger integer.
To find:
The integers
.
Solution:
Let the smaller even integer be x.
So, larger even integer is x+2 because they are consecutive even integers.
Seven times the smaller integer = 7x
-300 minus 4 times the larger integer = -300-4(x+2)
Now,
Divide both sides by 11.
So, the smaller even integer is -28.
So, the larger even integer is -26.
Answer:
B. No
Step-by-step explanation:
-A right angle triangle has two complimentary acute angles and one right angle.
-
is usually one of the acute angles and is equivalent to 90º minus it's complimentary acute angle.
-Complimentary angles add up to 90º.
#For complimentary angles:
The two acute angles cannot have the same Cosine value.
Hence, she's not correct.
7.90×7=55.30. 6.80×1=6.80. 55.30 + 6.80=62.10 Total
On the bottom left, the answer is subtraction property of equality because you need to subtract 4x to the 7x to simplify the equation.
Answer:
Step-by-step explanation:
If you can present a problem in Latex, you can do anything. I don't know what the question mark is for. I'm just ignoring it.
55 2/3 * 66 5/6
One of the ways to get the answer is to use decimals
55.666666667 * 66.833333333 = 3720.38889
Another way to do this problem is to break up one of the numbers
55 2/3 (66 + 5/6) You can do this if you know how to use the distributive property.
55 2/3 * 66 + 55 2/3 * 5/6
( (165 + 2) / 3) * 66 + (165 + 2)/3 * 5/6
167/3 * 66 + 167 / 3 * 5/6
167 * 22 + (167 * 5 / (3 * 6)
3674 + 835 / 18
3674 + 46 7/18
3720 7/18
If none of these seem right and you have choices, please list them.
