Life f passes through points (1,14) and (10,10). Line g is perpendicular to f. What is the slope of line g
1 answer:
The slope of line g is 9/4.
<u>Step-by-step explanation:</u>
The line f passes through points (1,14) and (10,10).
Line g is perpendicular to f.
<u>To find the slope of line f :</u>
The formula for slope is given by,
Here, The point (1,14) is (x1.y1) and (10,10) is (x2,y2).
⇒
⇒
Therefore, the slope of line f is -4/9.
<u>To find the slope of line g :</u>
Since, the line g is perpendicular to f, the slope of g will be the negative reciprocal of slope of line f.
⇒ slope of g = - (1 / slope of f).
⇒
⇒
∴ The slope of line g is 9/4.
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Answer:
y = cot(x - ⅓π) + 2
Step-by-step explanation:
The general equation for a cotangent function with the given properties is
y = Acot(Bx + C) + D, where
A = the stretching factor
π/|B| = the period
C = the phase shift (negative is to the right)
D = the vertical shift
A = 1
π/|B| = π, so1/|B| = 1 and B = 1
C = -⅓π
D = 2
The function is
y = cot(x - ⅓π) + 2
The figure below shows the graph of the function with the given parameters.
Note that the parent function y = cot(x) has the y-axis as an asymptote, so we can measure the phase shift by the movement of the asymptote π units to the right.
