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Anon25 [30]
3 years ago
15

A car completes a journey of 570 km at an average speed of 75 km/h calculate the time taken for the journey in hours and minutes

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
4 0
570/75=7 hours and 36 minutes
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The simplest fraction form of 0.0115 is
qaws [65]
0.0115 =  115 / 10000

= 115/10000      5 into 115 is 23, 5 into 10000 is 2000

= 23 / 2000    in its simplest form.

7 0
3 years ago
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16. At the mall, a pair of jeans cost $44 and a pair of earring cost $12. You spend a total of $80
sergij07 [2.7K]

There are 3 pairs of earrings that you bought in addition to the jeans. Forming an equation with the given values helps to find the required value.

<h3>How to write an equation for the given information?</h3>

It is given that,

A pair of jeans cost = $44

A pair of earrings cost = $12

you spent a total of $80 before taxes.

So, the equation for the given data is,

$80 = $44 + $12x

Where x is the number of pairs of earrings.

<h3>Calculation:</h3>

Simplifying the obtained equation:

$80 = $44 + $12x

⇒ 12x = 80 - 44

⇒ 12x = 36

⇒ x = 36/12

∴ x = 3

Thus, you can buy three pairs of earrings at the mall in addition to the jeans.

Learn more about an equation here:

brainly.com/question/25678139

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8 0
2 years ago
Round the decimal to a place of the underlined digit 5.657
kipiarov [429]

Answer:

5.6

Step-by-step explanation:

7 0
3 years ago
14.
FromTheMoon [43]

Answer:

  • a) 200 yards

Step-by-step explanation:

Difference in the distance = 50 yards

Difference in speed = 8 - 6 = 2 y/s

<u>Time to  cover the gap is:</u>

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<u>Sandra will run the distance:</u>

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8 0
2 years ago
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How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution?
Alex73 [517]
The solution is 25% acid, which means 2.5 liters acid (10 x .25). 
<span>you need that 2.5 liters to be 10%, or 1/10th the total. </span>
<span>the total would have to be 25 liters (2.5 x 10) so when you add to 10 to get 25 you get </span><span>15 liters. Hope I helped!</span>
3 0
3 years ago
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