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seraphim [82]
3 years ago
14

10 cards are numbered from 1 to 10 and placed in a box. One card is selected at random and is not replaced. Another card is then

randomly selected. What is the probability of selecting two prime numbers?
Mathematics
2 answers:
Rasek [7]3 years ago
6 0
16/100 is the probability Hope this helps
Vlada [557]3 years ago
4 0

The answer to your problem is 4/18

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Sharon has at most $25 to spend on her sister's birthday gift. She already bought a knitting machine for her, which cost $14.99.
Likurg_2 [28]

Answer:

$25 >= 14.99+2.75x

Step-by-step explanation:

7 0
2 years ago
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Find the volume of a cylinder with radius 5.7cm and height 10 cm, correct to 1 decimal place​
Veseljchak [2.6K]

\textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=5.7\\ h=10 \end{cases}\implies \begin{array}{llll} V=\pi (5.7)^2(10)\implies V=324.9\pi \\\\\\ V\approx 1020.7 \end{array}

8 0
1 year ago
PLEASE HELP!!
In-s [12.5K]

Answer:

345 miles

Step-by-step explanation:

So we know that 2 cities are 5.75 inches apart on the map and the scale reads for every 0.5 inch its 30 miles. So we can first start of by diving 5.75 by 0.5, since we need to know how many “0.5” inches are in 5.75 inches. You’d get 11.5. Now 11.5 multiply that by 30 which would get you 345 miles.

4 0
2 years ago
Texas University Quarterback, Michael Daniels, is standing on his own 10-yard line. He throws a pass tword the opposite goal lin
dimulka [17.4K]

Answer: The function is y=-\frac{28}{625}(x-35)^2+30.

Explanation:

It is given that Michael Daniels, is standing on his own 10-yard line. He throws a pass toward the opposite goal line. The football is 2 yards above the ground when the quarterback lets it go.

It follows a parabolic path. Reaching its highest point, 30 yards above the ground. It is caught 50 yards downfield at a point 2 yards above the ground.

So, the initial point is (10,2) and the other point is (60,2).

The height function of a football represents a downward parabola. The maximum point of the function is called vertex. So the vertex is (h,30).

The two point (10,2) and (60,2) have same y-coordinate, therefore the function is maximum at the midpoint of both points.

midpoint=(\frac{10+60}{2}, \frac{2+2}{2})=(35,2)

So, the function is maximum at x=35. Hence the vertex is (35,30)

The standard form of the parabola is,

y=a(x-h)^2+k

Where (h,k) is vertex and a is scale factor.

Since vertex is (35,30).

y=a(x-35)^2+30

The initial point is (10,2).

2=a(10-35)^2+30

-28=625a

a=-\frac{28}{625}

So the function of height is.

y=-\frac{28}{625}(x-35)^2+30

The graph of the function is shown below.

3 0
2 years ago
Multiples of 8 and 2
jarptica [38.1K]
16,24,32,40.48,56,64,72,80,88

7 0
3 years ago
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