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seraphim [82]
3 years ago
14

10 cards are numbered from 1 to 10 and placed in a box. One card is selected at random and is not replaced. Another card is then

randomly selected. What is the probability of selecting two prime numbers?
Mathematics
2 answers:
Rasek [7]3 years ago
6 0
16/100 is the probability Hope this helps
Vlada [557]3 years ago
4 0

The answer to your problem is 4/18

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Write in standard notation. 6.9 × 10^-3
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Step-by-step explanation:

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6 0
1 year ago
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m_a_m_a [10]
Here is my answer, hope to help you

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2 years ago
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Scorpion4ik [409]
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8 1/2 + 7 2/3 = Write the answer as a mixed number.
Digiron [165]

let's firstly convert the mixed fractions to improper fractions, and then add them up.

\bf \stackrel{mixed}{8\frac{1}{2}}\implies \cfrac{8\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{17}{2}}~\hfill \stackrel{mixed}{7\frac{2}{3}}\implies \cfrac{7\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{23}{3}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{17}{2}+\cfrac{23}{3}\implies \stackrel{\textit{using the LCD of 6}}{\cfrac{(3)17~~+~~(2)23}{6}}\implies \cfrac{51+46}{6}\implies \cfrac{97}{6}\implies 16\frac{1}{6}

7 0
2 years ago
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