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seraphim [82]
3 years ago
14

10 cards are numbered from 1 to 10 and placed in a box. One card is selected at random and is not replaced. Another card is then

randomly selected. What is the probability of selecting two prime numbers?
Mathematics
2 answers:
Rasek [7]3 years ago
6 0
16/100 is the probability Hope this helps
Vlada [557]3 years ago
4 0

The answer to your problem is 4/18

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5th grade math. Correct answer will be marked brainliest.
Likurg_2 [28]

Answer: 1,285, 1,282, 1,278

Step-by-step explanation:

4 0
2 years ago
In 5 years' time, Kate's father will be 3 times as old as Kate. Four years ago, her father
Brut [27]

Answer: Kate = 40/3  Her father = 50

Step-by-step explanation:

Let Kate's age in the present be K

And Kate's father's age in the present be F

3(K+5) = F+5

6(K-6) = F-6

Rearrange the first equation to get

3K+15 = F+5

3K+10 = F

Substitute that into the second question

6K-36 = 3K+10-6

3K = 40

K = 40/3

So F = 3*40/3+10 = 50

8 0
2 years ago
A manufactured lot of buggy whips has 20 items, of which 5 are defective. A random sample of 5 items is chosen to be inspected.
dimulka [17.4K]

Answer:

a. 39.55%

b. 44.02%

Step-by-step explanation:

We have the following data:

n = 5

x = 1

p = 5/20 = 0.25

to. If the sampling is done with replacement.

We apply the binomial distribution formula, which is as follows:

P = nCx * (p ^ x) * ((1-p) ^ (n-x))

Where nCx, is a combination, and is equal to:

nCx = n! / x! * (n-x)!

replacing we have:

5C1 = 5! / 1! * 4! = 5

replacing in the main formula:

P = 5 * (0.25 ^ 1) * ((1- 0.25) ^ (5-1))

P = 0.3955

that is, without replacing the probability is 39.55%

b. if the sampling is done without replacement.

Here it is a little different from the previous one, but what you should do is calculate three cases,

the first was the one at point a, when n = 5 and x = 1

5C1 = 5! / 1! * 4! = 5

the second is when n = 20 and x = 5, this is all possible scenarios.

20C5 = 20! / 5! * 15! = 15504

and the third is when n = 15 (20-5) and x = 4 (5-1), which corresponds to the cases when none were damaged

15C4 = 15! / 4! * 11! = 1365

In the end, it would be:

P = (5C1 * 15C4) / 20C5

Replacing:

P = 5 * 1365/15504

P = 0.4402

Which means that without replacing the probability is 44.02%

7 0
3 years ago
Georgina ran 3/8 mile in 3 minutes. How many miles does she run per minute?
Pachacha [2.7K]
In the given question we can see that the information,Georgina ran a distance of 3/8 mile in 3 minutes is already provided.
So
In 3 minutes Georgina can run a distance of = 3/8 miles
Then In 1 minute Georgina can run a distance of = 3/(8 * 3) miles
                                                                               = 3/24 miles
                                                                               = 1/8 miles.
So it can be said now that in 1 minute the distance that Georgina can cover is 1/8 miles. If required it can be converted to decimal value as well.

6 0
2 years ago
Read 2 more answers
46.The function f graphed above is the function f(x) = log2(x) + 2 for x > 0. Find a formula for the inverse of this function
pantera1 [17]

Answer:

The inverse for log₂(x) + 2  is - log₂x + 2.

Step-by-step explanation:

Given that

f(x) = log₂(x) + 2

Now to find the inverse of any function we put we replace x by 1/x.

f(x) = log₂(x) + 2

f(1/x) =g(x)= log₂(1/x) + 2

As we know that

log₂(a/b) = log₂a - log₂b

g(x) = log₂1 - log₂x + 2

We know that  log₂1 = 0

g(x) = 0 - log₂x + 2

g(x) =  - log₂x + 2

So the inverse for log₂(x) + 2  is - log₂x + 2.

3 0
3 years ago
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