10 cards are numbered from 1 to 10 and placed in a box. One card is selected at random and is not replaced. Another card is then
2 answers:
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We first need to factorize (if possible) the denominators:
we can see that
as 2 and 5 are two numbers whose sum is 7 and product is 10.
Similarly, we can see that
as 2 and 3 are two numbers whose sum is 5 and product is 6.
Thus, the expression is:
.
Now to make the denominators equal, but to also keep them as small as possible, the common denominator must be (p+3)(p+2)(p+5).
Answer: (p+3)(p+2)(p+5).
we can see that
Similarly, we can see that
Thus, the expression is:
Now to make the denominators equal, but to also keep them as small as possible, the common denominator must be (p+3)(p+2)(p+5).
Answer: (p+3)(p+2)(p+5).