3/4 is 6/8 and 7/8 is 7/8 so also is 6/7 i hope it helped u
Answer:
{27.5, 29, 34}.
Step-by-step explanation:
In order they are
24 27 28 28 29 31 32 36 38
The Median = middle value = 29.
Lower quartile = mean of 27 and 28 = 27.5.
Upper quartile = mean of 32 and 36 = 34.
Answer: x = 5
y = 2
z = 2
Step-by-step explanation:
-3x+4y+2z=-3 - ,- - - - - - 1
2x-4y-z=0 - - - - - - - - - - 2
y=3x-13 - - - - - - - - - - 3
We will use the method of substitution.
Substituting y = 3x -13 into equation 1 and equation 2, it becomes
-3x+4(3x-13)+2z=-3
-3x + 12x - 52 + 2z=-3+52
9x+2z = 49 - - - - - - -4
2x - 4(3x-13)-z= 0
2x - 12x + 52 - z = 0
-10x- z = -52 - - - - - - --5
Using elimination method to solve equation 4 and equation 5
Multiply equation 5 by 2 and equation 4 by 1
-20x - 2z = -104
9x+2z = 49
Adding both equations,
-11x = -55
x = -55/-11
x = 5
Substituting x = 5 into equation 3
y = 3x - 13
y = 3×5 -13 = 15-13
y = 2
Substituting x = 5 and y = 2 into equation 1,
-3x+4y+2z=-3
-3×5 + 4×2 +2z = -3
-15+8+2z = -3
-7+2z = -3
2z = -3+7
2z = 4
z = 4/2 = 2
Answer:
Number of Fares to airport is 25 and number of fares from airport is 25.
Step-by-step explanation:
Given:
Total Number of fares =50
Let number of fares to airport be x.
Let number of fares from airport be y.
hence the equation can be framed as;

Also Given
Total Money Collected = $375
Cost to airport = $10
Cost from Airport = $5
Total Money Collect is equal to Cost to airport multiplied by number of Fares to airport plus Cost from airport multiplied by number of Fare from airport.

Dividing by 5 on both side we get;

Now Subtracting equation 1 from 2 we get;

Substituting the value of x in equation 1 we get;

Hence Number of Fares to airport is 25 and number of fares from airport is 25.
I have no clue. I’m scared to get this type of math in the future.