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Paraphin [41]
3 years ago
11

The original cost of a cell phone is x dollars. The phone is

Mathematics
1 answer:
uranmaximum [27]3 years ago
7 0

Answer:

Hi

Step-by-step explanation:

I AM I HELPFUL

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write and equation of the line parallel to the line  2 x + 4 y = 20 2 x + 4 y = 20 and containing the point  ( −
MAXImum [283]

Answer:

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

m represents the slope of the line

c represents the y intercept

The equation of the given line is

2x + 4y = 20

4y = - 2x + 20

Dividing through by 4, it becomes

y = - x/2 + 5

Comparing with the slope intercept form, slope = - 1/2

If two lines are parallel, it means that they have the same slope. Therefore, the slope of the line passing through (- 6, 3) is - 1/2

To determine the y intercept, we would substitute m = - 1/2, x = - 6 and y = 3 into y = mx + c. It becomes

3 = - 1/2 × - 6 + c

3 = 3 + c

c = 3 - 3 = 0

The equation becomes

y = - x/2

4 0
2 years ago
Divid 15 into two parts such that the sum of their reciprocal is 3/10
emmasim [6.3K]
Let x and y be the 2 parts of 15 ==> x + y=15 (given)

Reciprocal of x and y ==> 1/x +1/y ==> 1/x + 1/y = 3/10 (given)


Let's solve  1/x + 1/y = 3/10 . Common denominator = 10.x.y (reduce to same denominator)

 ==> (10y+10x)/10xy = 3xy/10xy ==> 10x+10y =3xy

But x+y = 15 , then 10x+10y =150 ==> 150=3xy and xy = 50

Now we have the sum S of the 2 parts that is S = 15 and 
their Product = xy =50
Let's use the quadratic equation for S and P==> X² -SX +P =0
Or X² - 15X + 50=0, Solve for X & you will find:
The 1st part of 15 is 10 & the 2nd part is 5
4 0
3 years ago
can some one help me with this iv been stuck for about a week and i need some help are these function why or why not? thanks!
FromTheMoon [43]

Answer:

1) f(x) is not a function

2) g(x) is  a function.

Step-by-step explanation:

Function is  defined as a relationship between the independent variable and  the dependent variable

If a variable y is so related to a variable x that whenever a numerical value is assigned to x, there is a rule according to which a unique value of y is determined, then y is said to be a function of the independent variable

The above function can be represented by y = f(x).  f(x) can also been represented g(x) and P(x) functions of the independent variable x,  when the   function is unknown or unspecified.

Two laws to become a function:

a) Every element in X is related to some element in Y.

This relationship is commonly symbolized as y = f(x). In addition to f(x), other abbreviated symbols such as g(x) and P(x) are often used to represent functions of the independent variable x, especially when the nature of the function is unknown or unspecified.

Two rules to become a function:

a)"Each element" means that every element in X is related to some element in Y.

But some elements of Y may not assigned to x

b) A function is assigned to a single value. It will not give back 2 or more elements for the same input.

One-to-many is unaccepted, while many-to-one is accepted

If the relationship does not satisfies those two rules then it is not a function. we can say that the given relationship not a function.

1) Let f(x) be the function

Given x is domain ie, x=\{-2-3\} and y=f(x) ie, y=\{2,3\} is the range of x

By the definition of function,  f(x) does not satisfies the rules  to be a function because f(-2)=2 and f(-2)=3 So it assigns two values.

Therefore  f(x) is not a function

2) Let g(x) be the function

x is domain ie, x=\{-2-1,0,1\} and y=g(x) ie, y=\{2,2.5,3,3.5\} is the range of x

By the definition function,  g(x)  satisfies the rules  to be a function because g(-2)=3 , g(-1)=3.5,g(0)=2 and g(1)=2 So it assigns exactly one value.

Therefore  g(x) is  a function.

3 0
3 years ago
Given f'(x) = (1 − x)(4 − x), determine the intervals on which f(x) is increasing or decreasing.
Sophie [7]
The critical points are at x = 1 and x = 4 giving you the intervals (-inf, 1), (1, 4) and (4, inf).

By substituting x values in these 3 intervals, you can see that f'(x) is positive in the first and third intervals and negative in the second interval.

This means that f(x) is increasing in the first and third intervals and decreasing in the second interval.

The answer is D.
8 0
3 years ago
Read 2 more answers
What does DE equal to ?
guajiro [1.7K]
The answer to your question should be EF
4 0
3 years ago
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