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vitfil [10]
3 years ago
13

Solve using long division.

Mathematics
1 answer:
Mkey [24]3 years ago
6 0

Answer:

Quotient is 3x-5 and remainder is 0.

Step-by-step explanation:

Given:

Dividend = 3x^2+7x-20

Divisor = x+4

The long division is shown in the attachment.

Step 1: we need to divide 3x^2+7x-20 with x+4 we first multiply x+4 with 3x we get the remainder as -5x-20

Quotient as 3x.

Step 2: Now the dividend is -5x-20 and divisor x+4 now we will multiply x+4 with -5 we get the remainder as 0 and Quotient as 3x-5

Hence Quotient is 3x-5 and remainder is 0.

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In the school library, 28% of the books are non-fiction. If there are 1,224 fiction books in the library, what is the total numb
N76 [4]

Answer:

<em>There are 1700 books in the library.</em>

Step-by-step explanation:

<em>If 28% of the books is non-fiction, that means the remaining 72% of books are fiction.</em>

If 72% of the books are fiction, 1224/72 will give us 1%, which is 17.

If 1% is 17 books, then 17*100=100% of books.

There are 1700 books in the library.

8 0
3 years ago
If ADEF is reflected over the x-axis, what would be the coordinates of point F?
Brut [27]

Answer:

Please check the explanation.

Step-by-step explanation:

Let the coordinates of the point F be (x, y).

When a point F(x, y) is reflected over the x-axis, the x-coordinate of the point F remains the same, and the y-coordinate of the point reverses the sign.

Thus, the rule of reflection over the x-axis:

F(x, y)   →    F'(x, -y)

Here,

F'(x, -y) would be coordinates of point F after the reflection over the x-axis.

Let say, the point F(1, 2).

The coordinate of the point F after the reflection over the x-axis would be:

F(1, 2)   →    F'(1, -2)

Thus, F'(1, -2) would be the coordinates of point F after the reflection over the x-axis.

6 0
3 years ago
Find the zeros (roots) of the following equations. f(x) = 2x5 - 9x4 + 12x3 - 12x2 + 10x - 3 = 0
Talja [164]
Hi,
f(1)=2*1^5-9*1^4+12*1^3-12*1^2+10*1-3\\&#10;=2-9+12-12+10-3\\&#10;=0\\&#10;&#10;f(x)=(x-1)(2x^4-7x^3+5x^2-7x+3)\\&#10;&#10;&#10;g(x)=2x^4-7x^3+5x^2-7x+3\\&#10;&#10;g(3)=2*3^4-7*3^3+5*3^2-7*3+3\\&#10;=162-189+45-21+3\\&#10;=0\\&#10;&#10;g(x)=(x-3)(2x^3-x^2+2x-1)\\&#10;&#10;h(x)=2x^3-x^2+2x-1\\&#10;&#10;h( \dfrac{1}{2} )=2* \dfrac{1}{8} - \dfrac{1} {4}+1-1\\&#10;=0\\&#10;&#10;h(x)=(2x-1)(x^2+1)\\&#10;&#10;&#10;f(x)=(x-1)(x-3)(2x-1)(x+i)(x-i)\\&#10;&#10;&#10;
Roots are 1,3,0.5,i,-i.

8 0
3 years ago
F(x) = 5x - 3 for x = -7
erastovalidia [21]

Answer:

Step-by-step explanation:

f(-7) = 5(-7) - 3 = -35 - 3 = -38

6 0
3 years ago
It costs $100 to rent a bowling alley, plus $4 per person. The cost for any number (n) of people can be found using the expressi
AfilCa [17]

15*4+100

15+15+15+15 = 60

60+100 =

$160

7 0
3 years ago
Read 2 more answers
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