You have the following expression:

To verify the identity, you have that the left side of the equation becomes:
(1 + cosx)(1 - cosx) = (1 - cos^2 x)
because of the product of an expression by its conjugate result in a difference of squares. Or simplfy by expanding the factors and simplying.
Next, you have:
1 - cos^2 x = sin^2 x
because the Pythagorean identity.
Then, the identity is verified.
Answer:
Step-by-step explanation:
this is exactly the same as the 1st one, just they put it in a different orientation. sooo use law of cosines , where
QR = c
a = 12
b = 23
cos(120) = cos (P)
c = sq rt [ a^2+b^2﹣2*a*b*cos(P) ]
QR = sq rt [ 12^2 + 23^2 - 2* 12*23*cos(120) ]
QR = sq rt [ 144 + 529 - 552 * (-0.5 0 ]
QR = sq rt [ 673 + 276 ]
QR = sq rt [ 949 ]
QR = 30.8058
rounded to nearest 10th is
QR = 30.8 :)
<u>Answer:</u>

<u>Step-by-step explanation:</u>
32a^3 + 12a^2
To factorize this, start by taking the common variable out. As we have two powers for the same variable a, we can take the smaller power of a as a common to get like shown below:
32a^3 + 12a^2
a^2 (32a + 12)
Now when you have taken the variable as a common, try and take out a common number from the coefficient of a as well:
a^2 (32a + 12)
4a^2 (8a + 3)
So, the fully factored form of 32a^3 + 12a^2 is 4a^2 (8a + 3).
Answer:
![\sqrt[5]{b}^{2}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bb%7D%5E%7B2%7D)
Step-by-step explanation:
Step-by-step explanation:
J = 2b
M = J + 7
M = 21
J = 21 - 7
J = 14
B = 7
<em>Equation:</em>
If M is J+7, so then J = 21-7. J is 2*b, so 2*b = 21-7. Then you subtract and divide.