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3 years ago

Brian ran 414 miles in 34 of an hour. How fast was Brian running? 3316 mph 312 mph 5 mph 523 mph

Mathematics

2 answers:

alina1380 [7]3 years ago

5 0

Answer: Fourth option is correct.

Step-by-step explanation:

Since we have given that

Distance traveled by Brian = $4\frac{1}{4}\ miles=\frac{17}{4}\ miles$

Time taken by him = $\frac{3}{4}$ of an hour

So, Speed at which Brian is running fast is given by

$Speed=\dfrac{Distance}{Time}\\\\\\Speed=\dfrac{\dfrac{17}{4}}{\dfrac{3}{4}}\\\\\\Speed=\dfrac{17}{3}\\\\\\Speed=5\dfrac{2}{3}\ mph$

Hence, Brian was running fast at $5\dfrac{2}{3}\ mph$

Therefore, Fourth option is correct.

hammer [34]3 years ago

3 0

Answer:

he means 5 2/3

Step-by-step explanation:

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3 years ago

The variance can never bea.zerob.larger than the standard deviationc.negatived.smaller than the standard deviation

MrRa [10]

Answer:

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

Step-by-step explanation:

We need to remember that the variance is a measure of dispersion for a dataset respect to a measure of central tendency called the mean. The mean is defined as:

$\bar x = \frac{\sum_{i=1}^n X_i}{n}$

And the population mean is given by:

$\mu= \frac{\sum_{i=1}^n X_i}{N}$

The population variance is defined by:

$\sigma^2 = \frac{\sum_{i=1}^n (X_i -\mu)^2}{N}$

And the sample variance is defined as:

$s^2= \frac{\sum_{i=1}^n (X_i -\bar x)}{n-1}$

Now if we analyze the options we have this:

a.zero

False, if all the values are the same then the mean would be the same to the values and the difference between each value and the mean would 0 and indeed the variance would be 0.

b.larger than the standard deviation

False, if the population standard deviation is $\sigma=2$ then the variance would be $\sigma^2 = 4$ and as we can see is higher than the standard deviation

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

d.smaller than the standard deviation

False, if the population standard deviation is $\sigma=0.1$ then the variance would be $\sigma^2 = 0.01$ and as we can see is lower than the standard deviation

7 0

3 years ago

In the expression 2(10x) + 15y, x represents the number of hours Nina works in a week at a clothing store and y represents the n

ale4655 [162]

Answer:

The statement which is true in the choices is the third item in the choices such as "Nina makes 20x dollars at the clothing store each week". It was clearly stated in the given that x represent the total number of hours she worked in a week. This statement made the other items in the choices wrong.

Step-by-step explanation:

I hope this helps you :)

6 0

3 years ago

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